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# If p is a positive odd integer, what is the remainder when p

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Manager
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If p is a positive odd integer, what is the remainder when p [#permalink]

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26 Oct 2008, 05:51
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If p is a positive odd integer, what is the remainder when p is divided by 4 ?

(1) When p is divided by 8, the remainder is 5.
(2) p is the sum of the squares of two positive integers.

Any solution?
Thanks!
Actually it seems a simple question, but I seem to be getting a different answer to the answer guide

Kudos [?]: 54 [1], given: 0

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Joined: 05 Jul 2006
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26 Oct 2008, 06:00
[quote="prince13"]If p is a positive odd integer, what is the remainder when p is divided by 4 ?

(1) When p is divided by 8, the remainder is 5.
(2) p is the sum of the squares of two positive integers.

P = 8X+5....SUFF REMAINDER IS ALWAYS 1

p/4 = 8x/4 +5/4

FROM 2

INSUFF

1+9 = 10/4.........2

1+4 = 5/4............1

A

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Manager
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26 Oct 2008, 06:18
yezz wrote:
prince13 wrote:
If p is a positive odd integer, what is the remainder when p is divided by 4 ?

(1) When p is divided by 8, the remainder is 5.
(2) p is the sum of the squares of two positive integers.

P = 8X+5....SUFF REMAINDER IS ALWAYS 1

p/4 = 8x/4 +5/4

FROM 2

INSUFF

1+9 = 10/4.........2
1+4 = 5/4............1

A

I get the same answer as you. However, OA is D ... maybe OA is wrong

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26 Oct 2008, 07:06
[quote="yezz"][quote="prince13"]If p is a positive odd integer, what is the remainder when p is divided by 4 ?

(1) When p is divided by 8, the remainder is 5.
(2) p is the sum of the squares of two positive integers.

P = 8X+5....SUFF REMAINDER IS ALWAYS 1

p/4 = 8x/4 +5/4

FROM 2

SUFF

1+9 = 10/4.........2

1+49 = 50/4............2

D

iT WAS OUR MISTAKE ( THE QUESTIONS SAYS"Odd")

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26 Oct 2008, 07:13
D

(1) Here the remainder is always 1

(2) if the two integers are 1 and 2, then 1²+2² = 5 --- 5/4 remainder is 1
if the two integers are 2 and 5 then 2²+5² = 29 ---- 20/4 remainder is 1

what is the source of this question ??
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Manager
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26 Oct 2008, 08:38
yezz wrote:
iT WAS OUR MISTAKE ( THE QUESTIONS SAYS"Odd")

@yezz: Haha good point! Silly mistakes are still my downfall

@amitdgr: not sure of the original question source; a colleague who just did her GMATs gave me a list of practice questions to try.

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26 Oct 2008, 13:06
prince13 wrote:
If p is a positive odd integer, what is the remainder when p is divided by 4 ?

(1) When p is divided by 8, the remainder is 5.
(2) p is the sum of the squares of two positive integers.

Any solution?
Thanks!
Actually it seems a simple question, but I seem to be getting a different answer to the answer guide

agree that statement 1 is suff but how is st.2 suff?

2:
p = 1^2+ 2^2 = 5. the reminder is 1.
p = 1^2+ 3^2 = 10. the reminder is 2.

so st 2 is not suff.

so should be A.
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26 Oct 2008, 14:37
Initially - A
Changed to - D

Mistake: P has to be odd

Last edited by LiveStronger on 26 Oct 2008, 17:06, edited 1 time in total.

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26 Oct 2008, 18:40
GMAT TIGER wrote:
prince13 wrote:
If p is a positive odd integer, what is the remainder when p is divided by 4 ?

(1) When p is divided by 8, the remainder is 5.
(2) p is the sum of the squares of two positive integers.

Any solution?
Thanks!
Actually it seems a simple question, but I seem to be getting a different answer to the answer guide

agree that statement 1 is suff but how is st.2 suff?

2:
p = 1^2+ 2^2 = 5. the reminder is 1.
p = 1^2+ 3^2 = 10. the reminder is 2.

so st 2 is not suff.

so should be A.

hmmmm......

Did not see that P is an odd integer.
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Manager
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27 Oct 2008, 07:20
GMAT TIGER wrote:
Did not see that P is an odd integer.

It's sneakily tucked away in the question ... those writers are good!

First 7 words: "If p is a positive odd integer"

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27 Oct 2008, 18:06
prince13 wrote:
GMAT TIGER wrote:
Did not see that P is an odd integer.

It's sneakily tucked away in the question ... those writers are good!

First 7 words: "If p is a positive odd integer"

We are also good (in being stupid ) cuz we make them good.
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27 Oct 2008, 23:10
this one is tricky....in actual exam i would have been tricked.....good one !

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Re: DS: Remainder question   [#permalink] 27 Oct 2008, 23:10
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