If p is the product of integers from 1 to 30, inclusive : GMAT Problem Solving (PS)
Check GMAT Club Decision Tracker for the Latest School Decision Releases https://gmatclub.com/AppTrack

 It is currently 27 Feb 2017, 01:13

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# If p is the product of integers from 1 to 30, inclusive

Author Message
TAGS:

### Hide Tags

Intern
Joined: 05 Jul 2012
Posts: 12
Location: India
Concentration: Strategy, General Management
GMAT 1: 700 Q50 V37
GPA: 3.5
WE: Engineering (Computer Software)
Followers: 0

Kudos [?]: 50 [3] , given: 12

If p is the product of integers from 1 to 30, inclusive [#permalink]

### Show Tags

23 Aug 2012, 10:18
3
KUDOS
41
This post was
BOOKMARKED
00:00

Difficulty:

25% (medium)

Question Stats:

69% (02:03) correct 31% (01:30) wrong based on 1400 sessions

### HideShow timer Statistics

If p is the product of the integers from 1 to 30, inclusive, what is the greatest integer k for which 3^k is a factor of p ?

(A) 10
(B) 12
(C) 14
(D) 16
(E) 18
[Reveal] Spoiler: OA

Last edited by Bunuel on 12 Dec 2012, 04:36, edited 2 times in total.
Edited the question.
Director
Status: Tutor - BrushMyQuant
Joined: 05 Apr 2011
Posts: 583
Location: India
Concentration: Finance, Marketing
Schools: XLRI (A)
GMAT 1: 570 Q49 V19
GMAT 2: 700 Q51 V31
GPA: 3
WE: Information Technology (Computer Software)
Followers: 102

Kudos [?]: 578 [5] , given: 55

Re: 3^k is a factor of p [#permalink]

### Show Tags

23 Aug 2012, 19:27
5
KUDOS
1
This post was
BOOKMARKED
If p is the product of integers from 1 to 30, inclusive, what is the greatest integer k for which 3^k is a factor of p?

a) 10
b) 12
c) 14
d) 16
e) 18

Values which we are looking for are 3,6,9,12,.. all multiples till 30
now everything will give you atleast 1 power of 3 but there are values which will give more than 1 power of 3 and those values will be multiples of 9
9 -> will give 2 powers
18-> will give 2 powers
27 -> will give 3 powers
NUmber of single powers of 3 = (30-3)/3 +1 - 1(for 9) - 1(for 18) -1(for 27) = 7
so total powers = 2(for 9) + 2(for 18) + 3(for 27) + 7 = 14

Hope it helps!
_________________

Ankit

Check my Tutoring Site -> Brush My Quant

GMAT Quant Tutor
How to start GMAT preparations?
How to Improve Quant Score?
Gmatclub Topic Tags
Check out my GMAT debrief

How to Solve :
Statistics || Reflection of a line || Remainder Problems || Inequalities

Intern
Joined: 05 Jul 2012
Posts: 12
Location: India
Concentration: Strategy, General Management
GMAT 1: 700 Q50 V37
GPA: 3.5
WE: Engineering (Computer Software)
Followers: 0

Kudos [?]: 50 [0], given: 12

Re: 3^k is a factor of p [#permalink]

### Show Tags

23 Aug 2012, 21:07
Hi nkdotgupta,

Thanks for your reply but this is the explaation as provided in the OG. I wanted to know if there are other ways of approaching the problem since this method might be cumbersome we encounter larger numbers.

nktdotgupta wrote:
If p is the product of integers from 1 to 30, inclusive, what is the greatest integer k for which 3^k is a factor of p?

a) 10
b) 12
c) 14
d) 16
e) 18

Values which we are looking for are 3,6,9,12,.. all multiples till 30
now everything will give you atleast 1 power of 3 but there are values which will give more than 1 power of 3 and those values will be multiples of 9
9 -> will give 2 powers
18-> will give 2 powers
27 -> will give 3 powers
NUmber of single powers of 3 = (30-3)/3 +1 - 1(for 9) - 1(for 18) -1(for 27) = 7
so total powers = 2(for 9) + 2(for 18) + 3(for 27) + 7 = 14

Hope it helps!
Math Expert
Joined: 02 Sep 2009
Posts: 37135
Followers: 7262

Kudos [?]: 96742 [15] , given: 10781

If p is the product of integers from 1 to 30, inclusive [#permalink]

### Show Tags

24 Aug 2012, 00:55
15
KUDOS
Expert's post
42
This post was
BOOKMARKED
ajju2688 wrote:
If p is the product of integers from 1 to 30, inclusive, what is the greatest integer k for which $$3^k$$ is a factor of p?

a) 10
b) 12
c) 14
d) 16
e) 18

[Reveal] Spoiler:
c

This is an OG12 question. Can someone tell me if there is a quick way to solve these kinds of questions since the OG explanation seems to be very time consuming?

Finding the number of powers of a prime number k, in the n!.

The formula is:
$$\frac{n}{k}+\frac{n}{k^2}+\frac{n}{k^3}$$ ... till $$n>k^x$$

For example: what is the power of 2 in 25! (the highest value of m for which 2^m is a factor of 25!)
$$\frac{25}{2}+\frac{25}{4}+\frac{25}{8}+\frac{25}{16}=12+6+3+1=22$$. So the highest power of 2 in 25! is 22: $$2^{22}*k=25!$$, where k is the product of other multiple of 25!.

Check for more: everything-about-factorials-on-the-gmat-85592.html and math-number-theory-88376.html

Back to the original question:
If p is the product of integers from 1 to 30, inclusive, what is the greatest integer k for which $$3^k$$ is a factor of p?

A. 10
B. 12
C. 14
D. 16
E. 18

Given $$p=30!$$.

Now, we should check the highest power of 3 in 30!: $$\frac{30}{3}+\frac{30}{3^2}+\frac{30}{3^3}=10+3+1=14$$. So the highest power of 3 in 30! is 14.

Hope it's clear.
_________________
Intern
Joined: 05 Jul 2012
Posts: 12
Location: India
Concentration: Strategy, General Management
GMAT 1: 700 Q50 V37
GPA: 3.5
WE: Engineering (Computer Software)
Followers: 0

Kudos [?]: 50 [0], given: 12

Re: 3^k is a factor of p [#permalink]

### Show Tags

24 Aug 2012, 01:26
1
This post was
BOOKMARKED
Bunuel wrote:
ajju2688 wrote:
If p is the product of integers from 1 to 30, inclusive, what is the greatest integer k for which $$3^k$$ is a factor of p?

a) 10
b) 12
c) 14
d) 16
e) 18

[Reveal] Spoiler:
c

This is an OG12 question. Can someone tell me if there is a quick way to solve these kinds of questions since the OG explanation seems to be very time consuming?

Finding the number of powers of a prime number k, in the n!.

The formula is:
$$\frac{n}{k}+\frac{n}{k^2}+\frac{n}{k^3}$$ ... till $$n>k^x$$

For example: what is the power of 2 in 25! (the highest value of m for which 2^m is a factor of 25!)
$$\frac{25}{2}+\frac{25}{4}+\frac{25}{8}+\frac{25}{16}=12+6+3+1=22$$. So the highest power of 2 in 25! is 22: $$2^{22}*k=25!$$, where k is the product of other multiple of 25!.

Check for more: everything-about-factorials-on-the-gmat-85592.html and math-number-theory-88376.html

Back to the original question:
If p is the product of integers from 1 to 30, inclusive, what is the greatest integer k for which $$3^k$$ is a factor of p?

A. 10
B. 12
C. 14
D. 16
E. 18

Given $$p=30!$$.

Now, we should check the highest power of 3 in 30!: $$\frac{30}{3}+\frac{30}{3^2}+\frac{30}{3^3}=10+3+1=14$$. So the highest power of 3 in 30! is 1.

Hope it's clear.

Thanks Bunuel for the crystal clear explanation!
Intern
Status: Onward and upward!
Joined: 09 Apr 2013
Posts: 18
Location: United States
GMAT 1: Q V
Followers: 0

Kudos [?]: 15 [0], given: 72

Re: If p is the product of integers from 1 to 30, inclusive [#permalink]

### Show Tags

22 Oct 2013, 12:20
Correct me if I am mistaken but understanding number properties seems to be in line with these type of problems.

Going back to basics - these type of problems seem to relate to the factor foundation rule - if a is a factor of b and b is a factor of c then a is a factor of c.

In these problems you are trying to find the greatest degree of a common prime- in this case- of 3 in 30!.

Is this correct?
_________________

Kudos if my post was helpful!

Senior Manager
Joined: 15 Aug 2013
Posts: 328
Followers: 0

Kudos [?]: 56 [0], given: 23

Re: 3^k is a factor of p [#permalink]

### Show Tags

25 May 2014, 08:54
1
This post was
BOOKMARKED
Bunuel wrote:
ajju2688 wrote:
If p is the product of integers from 1 to 30, inclusive, what is the greatest integer k for which $$3^k$$ is a factor of p?

a) 10
b) 12
c) 14
d) 16
e) 18

[Reveal] Spoiler:
c

This is an OG12 question. Can someone tell me if there is a quick way to solve these kinds of questions since the OG explanation seems to be very time consuming?

Finding the number of powers of a prime number k, in the n!.

The formula is:
$$\frac{n}{k}+\frac{n}{k^2}+\frac{n}{k^3}$$ ... till $$n>k^x$$

For example: what is the power of 2 in 25! (the highest value of m for which 2^m is a factor of 25!)
$$\frac{25}{2}+\frac{25}{4}+\frac{25}{8}+\frac{25}{16}=12+6+3+1=22$$. So the highest power of 2 in 25! is 22: $$2^{22}*k=25!$$, where k is the product of other multiple of 25!.

Check for more: everything-about-factorials-on-the-gmat-85592.html and math-number-theory-88376.html

Back to the original question:
If p is the product of integers from 1 to 30, inclusive, what is the greatest integer k for which $$3^k$$ is a factor of p?

A. 10
B. 12
C. 14
D. 16
E. 18

Given $$p=30!$$.

Now, we should check the highest power of 3 in 30!: $$\frac{30}{3}+\frac{30}{3^2}+\frac{30}{3^3}=10+3+1=14$$. So the highest power of 3 in 30! is 1.

Hope it's clear.

Hi Bunuel,

This explanation makes complete sense but i'm curious as to why another method doesn't work.

I first found the number of integers (30-1+1) = 30
Average of 30+1/2 = 15.5

30 * 15.5 = 465

Factoring 465 only gave me one "3" and therefore I knew it was wrong but I had wasted valuable time. I realized that what I had done doesn't account for the product but rather the sumof the consecutive integers. Correct?

If the question was changed just a bit to say that "p" is the sum of the integers from 1 - 30 then my method would've worked and the answer would've been 1. Is that correct?
Math Expert
Joined: 02 Sep 2009
Posts: 37135
Followers: 7262

Kudos [?]: 96742 [0], given: 10781

Re: 3^k is a factor of p [#permalink]

### Show Tags

25 May 2014, 10:00
Expert's post
1
This post was
BOOKMARKED
russ9 wrote:
Bunuel wrote:
ajju2688 wrote:
If p is the product of integers from 1 to 30, inclusive, what is the greatest integer k for which $$3^k$$ is a factor of p?

a) 10
b) 12
c) 14
d) 16
e) 18

[Reveal] Spoiler:
c

This is an OG12 question. Can someone tell me if there is a quick way to solve these kinds of questions since the OG explanation seems to be very time consuming?

Finding the number of powers of a prime number k, in the n!.

The formula is:
$$\frac{n}{k}+\frac{n}{k^2}+\frac{n}{k^3}$$ ... till $$n>k^x$$

For example: what is the power of 2 in 25! (the highest value of m for which 2^m is a factor of 25!)
$$\frac{25}{2}+\frac{25}{4}+\frac{25}{8}+\frac{25}{16}=12+6+3+1=22$$. So the highest power of 2 in 25! is 22: $$2^{22}*k=25!$$, where k is the product of other multiple of 25!.

Check for more: everything-about-factorials-on-the-gmat-85592.html and math-number-theory-88376.html

Back to the original question:
If p is the product of integers from 1 to 30, inclusive, what is the greatest integer k for which $$3^k$$ is a factor of p?

A. 10
B. 12
C. 14
D. 16
E. 18

Given $$p=30!$$.

Now, we should check the highest power of 3 in 30!: $$\frac{30}{3}+\frac{30}{3^2}+\frac{30}{3^3}=10+3+1=14$$. So the highest power of 3 in 30! is 1.

Hope it's clear.

Hi Bunuel,

This explanation makes complete sense but i'm curious as to why another method doesn't work.

I first found the number of integers (30-1+1) = 30
Average of 30+1/2 = 15.5

30 * 15.5 = 465

Factoring 465 only gave me one "3" and therefore I knew it was wrong but I had wasted valuable time. I realized that what I had done doesn't account for the product but rather the sumof the consecutive integers. Correct?

If the question was changed just a bit to say that "p" is the sum of the integers from 1 - 30 then my method would've worked and the answer would've been 1. Is that correct?

Yes, you are correct. If it were "p is the SUM of integers from 1 to 30, inclusive", then the answer would be 1.
_________________
SVP
Status: The Best Or Nothing
Joined: 27 Dec 2012
Posts: 1858
Location: India
Concentration: General Management, Technology
WE: Information Technology (Computer Software)
Followers: 49

Kudos [?]: 1991 [4] , given: 193

Re: If p is the product of integers from 1 to 30, inclusive [#permalink]

### Show Tags

24 Jun 2014, 02:16
4
KUDOS
Just wrote down the multiples of 3 & the count of 3's in them

3 >> 1

6 >> 1

9 >> 2

12 > 1

15 > 1

18 > 2

21 > 1

24 > 1

27 > 3

30 > 1

Total = 14

_________________

Kindly press "+1 Kudos" to appreciate

Manager
Joined: 07 Apr 2014
Posts: 147
Followers: 1

Kudos [?]: 23 [0], given: 81

Re: If p is the product of integers from 1 to 30, inclusive [#permalink]

### Show Tags

11 Sep 2014, 11:17
ajju2688 wrote:
If p is the product of the integers from 1 to 30, inclusive, what is the greatest integer k for which 3^k is a factor of p ?

(A) 10
(B) 12
(C) 14
(D) 16
(E) 18

product of the integers from 1 to 30 = 30!

to find the greatest integer K i.e 3^k

30/3 +30/9 +30/27 = 10+3+1 =14
Manager
Joined: 16 Dec 2013
Posts: 52
Location: United States
GPA: 3.7
Followers: 0

Kudos [?]: 10 [1] , given: 38

Re: If p is the product of integers from 1 to 30, inclusive [#permalink]

### Show Tags

08 Mar 2015, 19:50
1
KUDOS
Bunuel wrote:
ajju2688 wrote:
If p is the product of integers from 1 to 30, inclusive, what is the greatest integer k for which $$3^k$$ is a factor of p?

a) 10
b) 12
c) 14
d) 16
e) 18

[Reveal] Spoiler:
c

This is an OG12 question. Can someone tell me if there is a quick way to solve these kinds of questions since the OG explanation seems to be very time consuming?

Finding the number of powers of a prime number k, in the n!.

The formula is:
$$\frac{n}{k}+\frac{n}{k^2}+\frac{n}{k^3}$$ ... till $$n>k^x$$

For example: what is the power of 2 in 25! (the highest value of m for which 2^m is a factor of 25!)
$$\frac{25}{2}+\frac{25}{4}+\frac{25}{8}+\frac{25}{16}=12+6+3+1=22$$. So the highest power of 2 in 25! is 22: $$2^{22}*k=25!$$, where k is the product of other multiple of 25!.

Check for more: everything-about-factorials-on-the-gmat-85592.html and math-number-theory-88376.html

Back to the original question:
If p is the product of integers from 1 to 30, inclusive, what is the greatest integer k for which $$3^k$$ is a factor of p?

A. 10
B. 12
C. 14
D. 16
E. 18

Given $$p=30!$$.

Now, we should check the highest power of 3 in 30!: $$\frac{30}{3}+\frac{30}{3^2}+\frac{30}{3^3}=10+3+1=14$$. So the highest power of 3 in 30! is 1.

Hope it's clear.

Br

Bunuel..."So the highest power of 3 in 30! is 1."...You mean 14 right?
Math Expert
Joined: 02 Sep 2009
Posts: 37135
Followers: 7262

Kudos [?]: 96742 [0], given: 10781

Re: If p is the product of integers from 1 to 30, inclusive [#permalink]

### Show Tags

08 Mar 2015, 19:53
Avinashs87 wrote:
Bunuel wrote:
ajju2688 wrote:
If p is the product of integers from 1 to 30, inclusive, what is the greatest integer k for which $$3^k$$ is a factor of p?

a) 10
b) 12
c) 14
d) 16
e) 18

[Reveal] Spoiler:
c

This is an OG12 question. Can someone tell me if there is a quick way to solve these kinds of questions since the OG explanation seems to be very time consuming?

Finding the number of powers of a prime number k, in the n!.

The formula is:
$$\frac{n}{k}+\frac{n}{k^2}+\frac{n}{k^3}$$ ... till $$n>k^x$$

For example: what is the power of 2 in 25! (the highest value of m for which 2^m is a factor of 25!)
$$\frac{25}{2}+\frac{25}{4}+\frac{25}{8}+\frac{25}{16}=12+6+3+1=22$$. So the highest power of 2 in 25! is 22: $$2^{22}*k=25!$$, where k is the product of other multiple of 25!.

Check for more: everything-about-factorials-on-the-gmat-85592.html and math-number-theory-88376.html

Back to the original question:
If p is the product of integers from 1 to 30, inclusive, what is the greatest integer k for which $$3^k$$ is a factor of p?

A. 10
B. 12
C. 14
D. 16
E. 18

Given $$p=30!$$.

Now, we should check the highest power of 3 in 30!: $$\frac{30}{3}+\frac{30}{3^2}+\frac{30}{3^3}=10+3+1=14$$. So the highest power of 3 in 30! is 1.

Hope it's clear.

Br

Bunuel..."So the highest power of 3 in 30! is 1."...You mean 14 right?

Yes, it's a typo. Edited. Thank you.
_________________
Manager
Status: A mind once opened never loses..!
Joined: 05 Mar 2015
Posts: 230
Location: India
MISSION : 800
WE: Design (Manufacturing)
Followers: 5

Kudos [?]: 91 [3] , given: 259

Re: If p is the product of integers from 1 to 30, inclusive [#permalink]

### Show Tags

09 Mar 2015, 00:29
3
KUDOS
ajju2688 wrote:
If p is the product of the integers from 1 to 30, inclusive, what is the greatest integer k for which 3^k is a factor of p ?

(A) 10
(B) 12
(C) 14
(D) 16
(E) 18

Simplest and the easy way
Plz find the attached picture

Attachments

A.png [ 10.77 KiB | Viewed 12255 times ]

_________________

Thank you

+KUDOS

> I CAN, I WILL <

Director
Status: Tutor - BrushMyQuant
Joined: 05 Apr 2011
Posts: 583
Location: India
Concentration: Finance, Marketing
Schools: XLRI (A)
GMAT 1: 570 Q49 V19
GMAT 2: 700 Q51 V31
GPA: 3
WE: Information Technology (Computer Software)
Followers: 102

Kudos [?]: 578 [0], given: 55

Re: If p is the product of integers from 1 to 30, inclusive [#permalink]

### Show Tags

14 Aug 2015, 13:40
ajju2688 wrote:
If p is the product of the integers from 1 to 30, inclusive, what is the greatest integer k for which 3^k is a factor of p ?

(A) 10
(B) 12
(C) 14
(D) 16
(E) 18

_________________

Ankit

Check my Tutoring Site -> Brush My Quant

GMAT Quant Tutor
How to start GMAT preparations?
How to Improve Quant Score?
Gmatclub Topic Tags
Check out my GMAT debrief

How to Solve :
Statistics || Reflection of a line || Remainder Problems || Inequalities

Manager
Joined: 10 Jun 2015
Posts: 128
Followers: 1

Kudos [?]: 25 [0], given: 0

Re: If p is the product of integers from 1 to 30, inclusive [#permalink]

### Show Tags

14 Aug 2015, 21:30
ajju2688 wrote:
If p is the product of the integers from 1 to 30, inclusive, what is the greatest integer k for which 3^k is a factor of p ?

(A) 10
(B) 12
(C) 14
(D) 16
(E) 18

you have to do successive division by 3. The given product is 30!
divide 30 by 3; the quotient is 10
divide 10 by 3; the quotient is 3
divide 3 by 3; the quotient is 1
Intern
Joined: 06 Oct 2015
Posts: 2
Followers: 0

Kudos [?]: 0 [0], given: 6

### Show Tags

22 Oct 2015, 05:18
If p is the product of the integers from 1 to 30, inclusive, what is the greatest integer k for which 3^k is a factor of p?

A) 10
B) 12
C) 14
D) 16
E) 18

What is the quickest way and how?
Math Forum Moderator
Joined: 20 Mar 2014
Posts: 2651
Concentration: Finance, Strategy
Schools: Kellogg '18 (M)
GMAT 1: 750 Q49 V44
GPA: 3.7
WE: Engineering (Aerospace and Defense)
Followers: 120

Kudos [?]: 1373 [1] , given: 789

Re: If p is the product of integers from 1 to 30, inclusive [#permalink]

### Show Tags

22 Oct 2015, 05:27
1
KUDOS
Expert's post
fayea wrote:
If p is the product of the integers from 1 to 30, inclusive, what is the greatest integer k for which 3^k is a factor of p?

A) 10
B) 12
C) 14
D) 16
E) 18

What is the quickest way and how?

The question has already been discussed.

Refer above for the solution.

Topics merged.

_________________

Thursday with Ron updated list as of July 1st, 2015: http://gmatclub.com/forum/consolidated-thursday-with-ron-list-for-all-the-sections-201006.html#p1544515
Inequalities tips: http://gmatclub.com/forum/inequalities-tips-and-hints-175001.html
Debrief, 650 to 750: http://gmatclub.com/forum/650-to-750-a-10-month-journey-to-the-score-203190.html

VP
Joined: 11 Sep 2015
Posts: 1088
Followers: 115

Kudos [?]: 1038 [0], given: 181

Re: If p is the product of integers from 1 to 30, inclusive [#permalink]

### Show Tags

22 Oct 2015, 09:18
ajju2688 wrote:
If p is the product of the integers from 1 to 30, inclusive, what is the greatest integer k for which 3^k is a factor of p ?

(A) 10
(B) 12
(C) 14
(D) 16
(E) 18

This question is really asking us to determine the number of 3's "hiding" in the prime factorization of p.

p = (1)(2)(3)(4)(5)(6)(7)(8)(9) . . . (27)(28)(29)(30)
= (1)(2)(3)(4)(5)(2)(3)(7)(8)(3)(3)(10)(11)(3)(4)(13)(14)(3)(5)(16)(17)(3)(3)(2)(19)(20)(3)(7)(22)(23)(3)(8)(25)(26). . . (3)(3)(3)(28)(29)(3)(10)
= (3)^14(other non-3 stuff)

Cheers,
Brent
_________________

Brent Hanneson – Founder of gmatprepnow.com

Optimus Prep Instructor
Joined: 06 Nov 2014
Posts: 1787
Followers: 54

Kudos [?]: 404 [0], given: 21

Re: If p is the product of integers from 1 to 30, inclusive [#permalink]

### Show Tags

22 Oct 2015, 21:21
fayea wrote:
If p is the product of the integers from 1 to 30, inclusive, what is the greatest integer k for which 3^k is a factor of p?

A) 10
B) 12
C) 14
D) 16
E) 18

What is the quickest way and how?

You need to find out the number of 3's in 30!

There is a direct formula for this:

$$[30/3] + [30/3^2] + [30/3^3]$$ = 10 + 3 + 1 = 14
Option C

Here [x] = integral part of the number
_________________

# Janielle Williams

Customer Support

Special Offer: $80-100/hr. Online Private Tutoring GMAT On Demand Course$299
Free Online Trial Hour

Intern
Joined: 30 Sep 2015
Posts: 8
Location: Portugal
GPA: 3.2
WE: Analyst (Investment Banking)
Followers: 0

Kudos [?]: 5 [0], given: 12

Re: If p is the product of integers from 1 to 30, inclusive [#permalink]

### Show Tags

30 Oct 2015, 09:58
Looking at the possible answers I understood what I should be looking for.

But was I the only one confused with the question, since "a factor is an integer that divides another integer without leaving a remainder"? What I mean is: having in mind the definition of a "factor", I could be looking for the biggest "factor", resulting from 3^k, and not the highest power of 3 in 30 (or the number of 3 in the prime factorization of p).

This is probably a dumb question, but I'm probably missing something that you guys are not and I want to be sure that I see it from now on.
Re: If p is the product of integers from 1 to 30, inclusive   [#permalink] 30 Oct 2015, 09:58

Go to page    1   2    Next  [ 29 posts ]

Similar topics Replies Last post
Similar
Topics:
3 If p is the product of the integers from 1 to 30, inclusive, wha 12 11 Jul 2010, 01:36
45 If p is the product of the integers from 1 to 30, inclusive 10 20 Jun 2010, 22:59
29 If p is the product of the integers from 1 to 30, inclusive, 11 16 Sep 2009, 09:54
31 If p is the product of the integers from 1 to 30, inclusive, what is t 11 09 Aug 2009, 11:10
1 If n is the product of the integers from 1 to 8, inclusive, 4 22 Aug 2007, 10:22
Display posts from previous: Sort by