It is currently 19 Oct 2017, 06:08

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

If Polygon X has fewer than 9 sides, how many sides does

  post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
CEO
CEO
User avatar
Joined: 21 Jan 2007
Posts: 2734

Kudos [?]: 1046 [0], given: 4

Location: New York City
If Polygon X has fewer than 9 sides, how many sides does [#permalink]

Show Tags

New post 20 Feb 2008, 08:22
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If Polygon X has fewer than 9 sides, how many sides does Polygon X have?

(1) The sum of the interior angles of Polygon X is divisible by 16.
(2) The sum of the interior angles of Polygon X is divisible by 15.
_________________

You tried your best and you failed miserably. The lesson is 'never try'. -Homer Simpson

Kudos [?]: 1046 [0], given: 4

Manager
Manager
avatar
Joined: 29 Jul 2007
Posts: 182

Kudos [?]: 36 [0], given: 0

Re: mgmat - prime factorization [#permalink]

Show Tags

New post 20 Feb 2008, 09:26
A.
sum of angles in polygon:
(n-2)*180

n<9

(n-2)*3^2* 2^2* 5

Statement II works for every n. insuff
Statement I will work if n = 6 as 6-2= 4. We need an extra 2^2 in our prime factorization to have the sum of angles divisible by 16.
if n = 6 --> (6-2)*3^2 *2^2 * 5
(4 *3^2 *4* 5)/16

Kudos [?]: 36 [0], given: 0

SVP
SVP
User avatar
Joined: 24 Aug 2006
Posts: 2130

Kudos [?]: 152 [0], given: 0

Re: mgmat - prime factorization [#permalink]

Show Tags

New post 20 Feb 2008, 09:29
bmwhype2 wrote:
If Polygon X has fewer than 9 sides, how many sides does Polygon X have?

(1) The sum of the interior angles of Polygon X is divisible by 16.
(2) The sum of the interior angles of Polygon X is divisible by 15.


The sum of the angles of any polygon = (#of sides - 2) * 180

Therefore,

6*180 = (2*3)(2*2*3*3*5)
5*180 = 5 (2*2*3*3*5)
4*180 = 2*2 (2*2*3*3*5)
3*180 = 3 (2*2*3*3*5)
2*180 = 2 (2*2*3*3*5)
1*180 = (2*2*3*3*5)

1) prime factors of 16 are 2*2*2*2 suff b/c only a hexagon has FOUR 2s in its prime factor set.

2) prime factors of 15 are 3*5 insuff, b/c all of the above polygons have these two prime factors.

I like A

Kudos [?]: 152 [0], given: 0

Director
Director
User avatar
Joined: 31 Mar 2007
Posts: 574

Kudos [?]: 80 [0], given: 0

Location: Canada eh
Re: mgmat - prime factorization [#permalink]

Show Tags

New post 20 Feb 2008, 11:13
A



hexagon.



Use (n-2)180

So check n = 3-8, ie 180 360 540 720 900 1080

180/16 = 11.25
360/16 = 22.5
540 = 33.75
720 = 45
900 = 56.25
1080 = 67.5

Hexagon.

Kudos [?]: 80 [0], given: 0

Re: mgmat - prime factorization   [#permalink] 20 Feb 2008, 11:13
Display posts from previous: Sort by

If Polygon X has fewer than 9 sides, how many sides does

  post reply Question banks Downloads My Bookmarks Reviews Important topics  


GMAT Club MBA Forum Home| About| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.