Walkabout wrote:

If Q is an odd number and the median of Q consecutive integers is 120, what is the largest of these integers?

(A) (Q - 1)/2 + 120

(B) Q/2 + 119

(C) Q/2 + 120

(D) (Q + 119)/2

(E) (Q + 120)/2

A very fast solution is to see what happens when Q =

1.

This means that there's only

ONE integer in the set.

So, if the median of the set is 120, then the set is {120}, which means the greatest value in the set is

120 So the correct answer choice should yield

120 when Q =

1.

a) (

1-1)/2 + 120 =

120 PERFECT!

b)

1/2 + 119 = some non-integer

c)

1/2 + 120 = some non-integer

d) (

1+119)/2 = 60

e) (

1+120)/2 = some non-integer

Since only answer choice A yield the correct output, it is the correct answer.

Cheers,

Brent

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