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If r and s are nonzero integers, is r/s an integer ?
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03 Oct 2018, 03:58
03 Oct 2018, 03:58
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If r and s are nonzero integers, is r/s an integer ?
(1) r - 1 = (s + 1)(s - 1)
(2) r - s = 20
(1) r - 1 = (s + 1)(s - 1)
(2) r - s = 20
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If r and s are nonzero integers, is r/s an integer ?
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Updated on: 04 Oct 2018, 13:30
Updated on: 04 Oct 2018, 13:30
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Bunuel
If r and s are nonzero integers, is r/s an integer ?
(1) r - 1 = (s + 1)(s - 1)
(2) r - s = 20
(1) r - 1 = (s + 1)(s - 1)
(2) r - s = 20
It is basically asking if r is divisible by s, in another words is r a multiple of s?
r - 1 = s^2 - 1
r = s^2
r/s = s^2/s = s which is an integer.
Sufficient
r - s = 20
If r = 25 and s = 5 then yes 25/5 = 5 integer
But if r = 26 and s = 6 we get no 26/6 = 13/3 not integer.
insufficient.
A is the answer choice.
Posted from my mobile device
Originally posted by Salsanousi on 03 Oct 2018, 04:09.
Last edited by Salsanousi on 04 Oct 2018, 13:30, edited 1 time in total.
Last edited by Salsanousi on 04 Oct 2018, 13:30, edited 1 time in total.
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Re: If r and s are nonzero integers, is r/s an integer ?
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03 Oct 2018, 04:11
03 Oct 2018, 04:11
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From statement 1:
r-1 = \(s^2\) - \(1^2\)
r = \(s^2\) or s = +r or -r.
So r/s is an integer.
Sufficient.
From statement 2:
r-s = 20.
Insufficient.
A is the answer.
r-1 = \(s^2\) - \(1^2\)
r = \(s^2\) or s = +r or -r.
So r/s is an integer.
Sufficient.
From statement 2:
r-s = 20.
Insufficient.
A is the answer.
