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# If T = 5/9 * (K - 32), and if T = 290, then K =

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If T = 5/9 * (K - 32), and if T = 290, then K = [#permalink]

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07 Dec 2012, 05:48
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If T = 5/9 * (K - 32), and if T = 290, then K =

(A) 1,738/9
(B) 322
(C) 490
(D) 554
(E) 2,898/5
[Reveal] Spoiler: OA
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Re: If T = 5/9 * (K - 32), and if T = 290, then K = [#permalink]

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06 Aug 2013, 22:55
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290=\frac{5}{9}(K-32)
58*9=k-31
i rounded 9 to 10 so
580-58+31=k
then i choose d, no point in doing calculations to waste time
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Re: If T = 5/9 * (K - 32), and if T = 290, then K = [#permalink]

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03 Sep 2014, 01:30
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$$290 = \frac{5}{9} * (k-32)$$

$$k = 290*\frac{9}{5} + 32$$

k = 58*9 + 32

Answer would be ending with 4; only option D = 554 fits in

Answer = D
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Re: If T = 5/9 * (K - 32), and if T = 290, then K = [#permalink]

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07 Dec 2012, 05:50
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Walkabout wrote:
If T = 5/9 * (K - 32), and if T = 290, then K =

(A) 1,738/9
(B) 322
(C) 490
(D) 554
(E) 2,898/5

Given that $$290=\frac{5}{9} * (K - 32)$$ --> $$290*\frac{9}{5}=K - 32$$ --> $$522=K-32$$ --> $$K=554$$.

Answer: D.
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Re: If T = 5/9 * (K - 32), and if T = 290, then K = [#permalink]

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09 Jun 2016, 13:05
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Walkabout wrote:
If T = 5/9 * (K - 32), and if T = 290, then K =

(A) 1,738/9
(B) 322
(C) 490
(D) 554
(E) 2,898/5

We start by substituting 290 for T and we obtain:

290 = 5/9(K – 32)

To eliminate the fraction, we multiply the entire equation by 9 and we have:

290 x 9 = 5(K – 32)

We next divide both sides by 5 and then solve for K:

58 x 9 = K – 32

522 = K – 32

554 = K

The answer is D.
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Re: If T = 5/9 * (K - 32), and if T = 290, then K = [#permalink]

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01 Sep 2014, 13:50
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Re: If T = 5/9 * (K - 32), and if T = 290, then K = [#permalink]

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14 Jul 2015, 03:06
Can someone please explain the algebra that the previous poster used. How did they jump from the 1st equation to the 2nd?
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Re: If T = 5/9 * (K - 32), and if T = 290, then K = [#permalink]

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14 Jul 2015, 03:14
jackrim1 wrote:
Can someone please explain the algebra that the previous poster used. How did they jump from the 1st equation to the 2nd?

Sure, look below:

Given: T = 5/9 * (K - 32) ----> Multiply both sides by 9/5, we get ----> 9/5T = (5/9 * 9/5) * (K-32)

----> 9/5 * T = 1 * (K-32) ----> (9/5 )T = K -32 (as x*1 = x) ----> Now add 32 to both sides (to transfer 32 from K-32 towards T), we get ----> (9/5)T + 32 = K

Now susbtitute T = 290 in the last equation, we get

(9/5) * 290 + 32 = K ----> K = 9 *58 + 32 = 522 + 32 = 544.
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Re: If T = 5/9 * (K - 32), and if T = 290, then K = [#permalink]

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14 Jul 2015, 04:28
Ah they multiplied by the reciprocal, I misunderstood that.

Thanks
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Re: If T = 5/9 * (K - 32), and if T = 290, then K = [#permalink]

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14 Jul 2015, 05:59
Walkabout wrote:
If T = 5/9 * (K - 32), and if T = 290, then K =

(A) 1,738/9
(B) 322
(C) 490
(D) 554
(E) 2,898/5

$$290 * 9 = 5 * (K - 32)$$
$$K = \frac{(290*9) + 32}{5}$$
$$K = 554.$$ Ans (D).
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Re: If T = 5/9 * (K - 32), and if T = 290, then K = [#permalink]

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14 Jul 2015, 09:18
Just want to remind everyone to use estimation for problems such as this one. You will multiply 290 by something slightly less than 2 and then add 32. We know it is a whole number and greater than 500, only D is that...
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Re: If T = 5/9 * (K - 32), and if T = 290, then K = [#permalink]

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14 Jul 2015, 09:48
Very good point. What's your strategy upon seeing a question such as that and deciding which tactic to use?
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Re: If T = 5/9 * (K - 32), and if T = 290, then K = [#permalink]

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14 Jul 2015, 09:52
Honestly, it is something that you should be looking at most of the time. This is a thinking exam, not at math exam.
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Re: If T = 5/9 * (K - 32), and if T = 290, then K = [#permalink]

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14 Jul 2015, 10:46
True, but if you do attempt to answer a question without doing math then there's a higher risk of getting muddled or making careless errors. There's obviously a balancing act and it'd be preferable to have some sort of guidelines to apply in choosing how to tackle a problem
Re: If T = 5/9 * (K - 32), and if T = 290, then K =   [#permalink] 14 Jul 2015, 10:46
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# If T = 5/9 * (K - 32), and if T = 290, then K =

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