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If the area of the circle above is 64π, what is the value of k
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08 Nov 2018, 04:32
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If the area of the circle above is 64\(π\), what is the value of k ? (A) 2 (B) 8/3 (C) 4 (D) 16/3 (E) 12 Project PS Butler : Question #05 Subscribe to get Daily Email  Click Here  Subscribe via RSS  RSS
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Re: If the area of the circle above is 64π, what is the value of k
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08 Nov 2018, 04:58
HKD1710 wrote: If the area of the circle above is \(64π\), what is the value of \(k\) ? (A) 2 (B) 8/3 (C) 4 (D) 16/3 (E) 12 Project PS Butler : Question #05 Subscribe to get Daily Email  Click Here  Subscribe via RSS  RSSArea of circle \(pi*r^2 = 64\) > R = 8 if Radius = 8 then diametr is 16 length of diametre of circle is \(4kk=16\) > \(3k =16\) > k =\(\frac{16}{3}\) IMO: D




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Re: If the area of the circle above is 64π, what is the value of k
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08 Nov 2018, 05:28
\(64*pi = r^2 *pi\)
r = 8
radius = 3k  1.5k = 1.5k
radius = \(1.5k = \frac{3}{2}* k\)
\(\frac{3}{2} * k = 8\)
\(k = \frac{16}{3}\)
Answer choice D



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Re: If the area of the circle above is 64π, what is the value of k
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08 Nov 2018, 09:50
As per the given figure.... the diameter of the cicle = \(4kk=3k\) Hence, the \(radius(r) = \frac{3k}{2}\) Thus the area of the circle = \(r^2 * π = 64π\) or , \(r^2 = 64\) or , \(r = 8\) or \(\frac{3k}{2} = 8\) or \(k =\frac{8*2}{3} = \frac{16}{3}\)............ Ans D
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If the area of the circle above is 64π, what is the value of k
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08 Nov 2018, 09:55
HKD1710 wrote: As per the given figure.... the diameter of the cicle = \(4kk=3k\) Hence, the \(radius(r) = \frac{3k}{2}\) Thus the area of the circle = \(r^2 * π = 64π\) or , \(r^2 = 64\) or , \(r = 8\) or \(\frac{3k}{2} = 8\) or \(k =\frac{8*2}{3} = \frac{16}{3}\)............Ans D HKD1710 why did post solution in the wrong place



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Re: If the area of the circle above is 64π, what is the value of k
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08 Nov 2018, 10:30
dave13 wrote: HKD1710 wrote: As per the given figure.... the diameter of the cicle = \(4kk=3k\) Hence, the \(radius(r) = \frac{3k}{2}\) Thus the area of the circle = \(r^2 * π = 64π\) or , \(r^2 = 64\) or , \(r = 8\) or \(\frac{3k}{2} = 8\) or \(k =\frac{8*2}{3} = \frac{16}{3}\)............Ans D HKD1710 why did post solution in the wrong place Hi dave13, Someone edited the question by mistake with solution. I have corrected it now. As you can see in the first reply that you only made , that the question was correctly posted. :D
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Re: If the area of the circle above is 64π, what is the value of k
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08 Nov 2018, 12:22
HKD1710 wrote: dave13 wrote: HKD1710 wrote: As per the given figure.... the diameter of the cicle = \(4kk=3k\) Hence, the \(radius(r) = \frac{3k}{2}\) Thus the area of the circle = \(r^2 * π = 64π\) or , \(r^2 = 64\) or , \(r = 8\) or \(\frac{3k}{2} = 8\) or \(k =\frac{8*2}{3} = \frac{16}{3}\)............Ans D HKD1710 why did post solution in the wrong place Hi dave13, Someone edited the question by mistake with solution. I have corrected it now. As you can see in the first reply that you only made , that the question was correctly posted. :D ....... That moron was me ?...... sry for the confusion HKD1710
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Re: If the area of the circle above is 64π, what is the value of k &nbs
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08 Nov 2018, 12:22






