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If the average (arithmetic mean) of 4 different numbers is 3

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danzig
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If the average (arithmetic mean) of 4 different numbers is 3 [#permalink] New post   22 Oct 2012, 06:03
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If the average (arithmetic mean) of 4 different numbers is 30, how many of the numbers are less than 30?

(1) The median of the numbers is 30.
(2) The largest and smallest of the numbers are odd, and the two middle numbers are even.

Is there an alternative method instead of picking numbers?
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MacFauz
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Re: If the average (arithmetic mean) of 4 different numbers is 3 [#permalink] New post   22 Oct 2012, 08:04
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1) There are four numbers and the median is 30. So the average of the 2nd highest number and the 3rd highest number is 30. Since the numbers are all different, they cannot both be 30. So one has to be higher than 30 while the other has to be lower. So two numbers are lesser than 30. The fact that the average is 30 does not even have to be used here. Sufficient.

2) This statement does not give any valuable information. I think we can easily form two different sets that satisfy the given conditions although I have no idea how to do it without picking numbers. Insufficient.

Hence answer is A.

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Re: If the average (arithmetic mean) of 4 different numbers is 3 [#permalink] New post   19 Nov 2013, 15:15
If the 4 numbers are different, "at least one is <30 and two are >30" or "at least one is >30 and two are <30"

1) Tells you that none of them are = 30, so two will be >30 and two will be <30.

2) Tells you nothing.


IMO A
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Re: If the average (arithmetic mean) of 4 different numbers is 3 [#permalink] New post   30 Apr 2014, 09:12
MacFauz wrote:
1) There are four numbers and the median is 30. So the average of the 2nd highest number and the 3rd highest number is 30. Since the numbers are all different, they cannot both be 30. So one has to be higher than 30 while the other has to be lower. So two numbers are lesser than 30. The fact that the average is 30 does not even have to be used here. Sufficient.

2) This statement does not give any valuable information. I think we can easily form two different sets that satisfy the given conditions although I have no idea how to do it without picking numbers. Insufficient.

Hence answer is A.

Kudos Please.... If my post helped


Can we get some valuable example from Statement 2 in this case?

Thanks!
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J :)
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Re: If the average (arithmetic mean) of 4 different numbers is 3 [#permalink] New post   30 Apr 2014, 09:46
11,20,30,59 - Two numbers are lesser than 30.
11,26,28,55 - Three numbers are lesser than 30.
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Re: If the average (arithmetic mean) of 4 different numbers is 3 [#permalink] New post   10 Jun 2021, 11:43
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: If the average (arithmetic mean) of 4 different numbers is 3 [#permalink]
10 Jun 2021, 11:43
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