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# If the average (arithmetic mean) of 5 different numbers is

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Manager
Joined: 06 Nov 2008
Posts: 53

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If the average (arithmetic mean) of 5 different numbers is [#permalink]

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14 Nov 2008, 17:19
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If the average (arithmetic mean) of 5 different numbers is 12, what is the median of the 5 numbers?
(1) The median of the 5 numbers is equal to 1/3 of the sum of the 4 numbers other than the median.
(2) The sum of the 4 numbers other than the median is equal to 45.

A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.

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Manager
Joined: 12 Oct 2008
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14 Nov 2008, 17:28
i think it is D

1) (x+y+z+a+b)/5=12, therefore x+y+z+a+b=60. Lets say that x is median, and lets rename y+z+a+b to c, so x+c=60 and x/3=c ... we can solve this, therefore suff.

2)(45+x)/5=60 suff.

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Re: median--26   [#permalink] 14 Nov 2008, 17:28
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# If the average (arithmetic mean) of 5 different numbers is

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