Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized for You
we will pick new questions that match your level based on your Timer History
Track Your Progress
every week, we’ll send you an estimated GMAT score based on your performance
Practice Pays
we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:
If the average (arithmetic mean) of five consecutive negative integers
[#permalink]
Show Tags
17 Oct 2018, 01:46
1
00:00
A
B
C
D
E
Difficulty:
(N/A)
Question Stats:
78% (01:40) correct 22% (02:11) wrong based on 63 sessions
HideShow timer Statistics
If the average (arithmetic mean) of five consecutive negative integers is 2k – 1, what is the difference between the greatest and least of the five integers?
If the average (arithmetic mean) of five consecutive negative integers
[#permalink]
Show Tags
17 Oct 2018, 02:38
\(\frac{sum of numbers}{number of numbers}\) =average, or \(\frac{sum of observations}{n}\)=arithmetic mean We don't know what those numbers are so 'n'. The numbers are consecutive so we can minus one each time. \(\frac{n+(n-1)+(n-2)+(n-3)+(n-4)}{5}\) = 2k-1 \(\frac{5n-10}{5}\)=2k-1 n-2=2k-1 n=2k+1
Sub in 2k+1 for the numbers above 2k+1, 2k, 2k-1, 2k-2, 2k-3
Difference is subtraction. Doesn't matter if they are positive or negative numbers, difference is still the same (e.g. -5--2=-3=3, or if absolutes are familiar |-5|-|-2|=5-2=3 |2k+1|-|2k-3| 2k+3-2k+1 = 4
close
78% (01:40) correct 
