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If the average(arithmetic mean) of four numbers is 10 ,how many of the

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If the average(arithmetic mean) of four numbers is 10 ,how many of the  [#permalink]

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New post 27 Feb 2015, 21:22
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If the average(arithmetic mean) of four numbers is 10 ,how many of the numbers are greater than 10?

1) Precisely two numbers are equal to 10

2) The largest of the 4 numbers is 10 greater than the smallest of the 4 numbers.
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Re: If the average(arithmetic mean) of four numbers is 10 ,how many of the  [#permalink]

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New post 27 Feb 2015, 23:53
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Hi AverageGuy123,

This question has some very specific 'restrictions' to it, but if you take the proper notes and TEST VALUES, you can answer this question without too much trouble.

We're told that the average of 4 numbers is 10. We're asked how many (of those 4) are greater than 10.

From the first sentence, we can create an equation:

(W + X + Y + Z)/4 = 10
W + X + Y + Z = 40

Fact 1: Precisely 2 of the numbers equal 10

I'm going to "lock in" the W and the X as 10s....

10 + 10 + Y + Z = 40
Y + Z = 20

Since Fact 1 states that PRECISELY 2 of the numbers equal 10, neither Y nor Z can now be 10s. That means we need 2 numbers that add up to 20 and NEITHER can be a 10...

9 and 11
8 and 12
0 and 20
-1 and 21
Etc.
In EVERY possible example, one number is LESS than 10 and ONE number is GREATER than 10. Thus, the answer to the question is ALWAYS ONE number.
Fact 1 is SUFFICIENT

Fact 2: The largest of the numbers is 10 greater than the smallest of the numbers

IF... the numbers are....
5, 10, 10 and 15.... then the answer to the question is ONE.
4, 10, 12 and 14.... then the answer to the question is TWO.
Fact 2 is INSUFFICIENT.

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Re: If the average(arithmetic mean) of four numbers is 10 ,how many of the  [#permalink]

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New post 23 Feb 2016, 19:16
now this one is a very tricky one...precisely 2..so other 2 cannot be 10...A for sure...
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Re: If the average(arithmetic mean) of four numbers is 10 ,how many of the  [#permalink]

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New post 09 Mar 2017, 15:41
mvictor wrote:
now this one is a very tricky one...precisely 2..so other 2 cannot be 10...A for sure...


I dont agree with this no where it is written that the other two numbers can't be 10 and 10.
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Re: If the average(arithmetic mean) of four numbers is 10 ,how many of the  [#permalink]

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New post 09 Mar 2017, 15:46
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sandeep211986 wrote:
mvictor wrote:
now this one is a very tricky one...precisely 2..so other 2 cannot be 10...A for sure...


I dont agree with this no where it is written that the other two numbers can't be 10 and 10.



it clearly says that only 2 are 10:

1) Precisely two numbers are equal to 10
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Re: If the average(arithmetic mean) of four numbers is 10 ,how many of the  [#permalink]

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New post 09 Mar 2017, 16:31
AverageGuy123 wrote:
If the average(arithmetic mean) of four numbers is 10 ,how many of the numbers are greater than 10?

1) Precisely two numbers are equal to 10

2) The largest of the 4 numbers is 10 greater than the smallest of the 4 numbers.


Assume that \(a\), \(b\), \(c\) and \(d\) are four numbers, where \(a \leq b \leq c \leq d\).
Then we have 1 equation that \(a + b + c + d = 40\).

Let's translate the conditions to mathematical expressions.

1) \(b = c = 10\), \(a < 10\), \(d > 10\)
2) \(d = a + 10\)

For the first condition, only \(d\) is greater than 10 form the above mathematical expression.
Hence the condition 1) is sufficient.

For the second condition, we have following examples.
Let \(a = 5\) and \(d = 15\).
Then we have two kinds of cases as follows.
5, 10, 10, 15 : They have just 1 number of elements greater than 10, which is just 15.
5, 9, 11, 15 : They have 2 numbers of elements greater than 10, which are 11 and 15.
Hence, we don't have a unique solution about the question how many numbers are greater than 10.
Therefore, the second condition is not sufficient.

Please remind that we should forget everything about the condition 1), when we consider the second condition only.
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Re: If the average(arithmetic mean) of four numbers is 10 ,how many of the  [#permalink]

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New post 25 Sep 2017, 22:44
sandeep211986 wrote:
mvictor wrote:
now this one is a very tricky one...precisely 2..so other 2 cannot be 10...A for sure...


I dont agree with this no where it is written that the other two numbers can't be 10 and 10.



I just made the same mistake. :)
Re: If the average(arithmetic mean) of four numbers is 10 ,how many of the &nbs [#permalink] 25 Sep 2017, 22:44
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