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If the average (arithmetic mean) of p and r is n and the average (arit

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Bunuel
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If the average (arithmetic mean) of p and r is n and the average (arit [#permalink] If the average (arithmetic mean) of p and r is n and the average (arit   24 Oct 2019, 01:39
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81% (01:06) correct 19% (01:38) wrong based on 68 sessions
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If the average (arithmetic mean) of p and r is n and the average (arithmetic mean) of r and s is 3n, what is the value of s – p?

A. 4n
B. 2n
C. n
D. n + r
E. n + 2r
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A
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Re: If the average (arithmetic mean) of p and r is n and the average (arit [#permalink] If the average (arithmetic mean) of p and r is n and the average (arit   24 Oct 2019, 03:17
Bunuel wrote:
If the average (arithmetic mean) of p and r is n and the average (arithmetic mean) of r and s is 3n, what is the value of s – p?

A. 4n
B. 2n
C. n
D. n + r
E. n + 2r



p + r /2 = n

p + r = 2n..................1

again,

r + s/2 = 3n

r + s = 6n ..................2


s + r = 6n

r + p = 2n

...........................deduct

s - p = 4n.

A is the correct answer.
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Re: If the average (arithmetic mean) of p and r is n and the average (arit [#permalink] If the average (arithmetic mean) of p and r is n and the average (arit   24 Oct 2019, 08:20
Bunuel wrote:
If the average (arithmetic mean) of p and r is n and the average (arithmetic mean) of r and s is 3n, what is the value of s – p?

A. 4n
B. 2n
C. n
D. n + r
E. n + 2r


\(\frac{p + r}{2} = n\)

Or, \(p + r = 2n\)

Or, \(p = 2n - r\)

And, \(\frac{r + s}{2}= 3n\)

Or, \(r + s = 6n\)

Or, \(s = 6n - r\)

Now, \(s – p = ( 6n - r ) - ( 2n - r )\)

Or, \(s – p = 6n - r - 2n + r\)

Or, \(s – p = 4n\), Answer must be (A)
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Re: If the average (arithmetic mean) of p and r is n and the average (arit [#permalink] If the average (arithmetic mean) of p and r is n and the average (arit   26 Oct 2019, 08:58
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Bunuel wrote:
If the average (arithmetic mean) of p and r is n and the average (arithmetic mean) of r and s is 3n, what is the value of s – p?

A. 4n
B. 2n
C. n
D. n + r
E. n + 2r


We can create the equations:

(p + r)/2 = n

p + r = 2n

p = 2n - r

and

(r + s)/2 = 3n

r + s = 6n

s = 6n - r

Thus, s - p = (6n - r) - (2n - r) = 4n.

Answer: A
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Re: If the average (arithmetic mean) of p and r is n and the average (arit [#permalink]
26 Oct 2019, 08:58
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Bunuel
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