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# If the average (arithmetic mean0 of 5 different numbers is

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If the average (arithmetic mean0 of 5 different numbers is [#permalink]

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05 Jul 2008, 11:08
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If the average (arithmetic mean0 of 5 different numbers is 12, what is the median of the numbers?
(1) The median of the 5 numbers is equal to 1/3 of the sum of the 4 numbers other than the median.
(2) The sum of th 4 numbers other than the median is equal o 45.
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Re: If the average [#permalink]

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05 Jul 2008, 11:16
each option is alone sufficient to solve.
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Re: If the average [#permalink]

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05 Jul 2008, 12:30
GMBA85 wrote:
each option is alone sufficient to solve.

can you please explain
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Re: If the average [#permalink]

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06 Jul 2008, 18:40
TheBigCheese wrote:
GMBA85 wrote:
each option is alone sufficient to solve.

can you please explain

If the average (arithmetic mean0 of 5 different numbers is 12, what is the median of the numbers?
(1) The median of the 5 numbers is equal to 1/3 of the sum of the 4 numbers other than the median.
(2) The sum of th 4 numbers other than the median is equal o 45.

arithmetic mean0 of 5 different numbers is 12
=>Sum of 5 numbers = 12*5 = 60
Let M be the median

stat1
M = 1/3 *sum4
=> sum5 = sum4+M
60 = sum4 + sum4/3
Suff..we can calculate M from sum4
stat2
sum4 = 45
M = 60-sum4
Suff

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Re: If the average   [#permalink] 06 Jul 2008, 18:40
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# If the average (arithmetic mean0 of 5 different numbers is

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