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If the average of five numbers is -10, and the sum of three of the num

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If the average of five numbers is -10, and the sum of three of the num [#permalink]

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New post 10 Mar 2017, 09:28
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A
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C
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E

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  5% (low)

Question Stats:

100% (00:59) correct 0% (00:00) wrong based on 33 sessions

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If the average of five numbers is -10, and the sum of three of the numbers is 16, then what is the average of the other two numbers?

(A) –33

(B) –1

(C) 5

(D) 20

(E) 25
[Reveal] Spoiler: OA

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Re: If the average of five numbers is -10, and the sum of three of the num [#permalink]

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New post 10 Mar 2017, 09:45
If the average of 5 numbers is -10 then the sum of the five will be 5*(-10) = -50

=> x1+x2+x3+x4+x5 = - 50 and we know that the sum of three number is 16

Then x1+x2+ 16 = - 50 => x1+x2= -66 to find the average we divide by two equal to -33 => Answer A

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Re: If the average of five numbers is -10, and the sum of three of the num [#permalink]

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New post 07 Aug 2017, 18:08
Sum(5) => -10*5 => -50

Sum(3) => 16
Sum(2) => -50-16 => -66

Average => -66/2 => -33

Hence A.
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Re: If the average of five numbers is -10, and the sum of three of the num [#permalink]

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New post 07 Aug 2017, 19:56
If the sum of two number is x,

\(\frac{16 + x}{5} = -10\)(from question stem)
\(16+ x = -50\)
\(x = -50 - 16 = -66\)
Hence, average of 2 numbers is \(\frac{-66}{2} = -33\)(Option A)
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Re: If the average of five numbers is -10, and the sum of three of the num   [#permalink] 07 Aug 2017, 19:56
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