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If the crime rate in a certain region dropped by 28% last year to a ra

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If the crime rate in a certain region dropped by 28% last year to a ra  [#permalink]

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New post 07 Apr 2019, 04:56
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Question Stats:

44% (01:52) correct 56% (02:36) wrong based on 27 sessions

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If the crime rate in a certain region dropped by 28% last year to a rate of 500 crimes per 100,000 citizens, what was the approximate rate before the drop?

A. 500 crimes per 128,000 citizens

B. 640 crimes per 128,000 citizens

C. 695 crimes per 128,000 citizens

D. 640 crimes per 100,000 citizens

E. 695 crimes per 100,000 citizens

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Re: If the crime rate in a certain region dropped by 28% last year to a ra  [#permalink]

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New post 07 Apr 2019, 08:05
AkshdeepS wrote:
If the crime rate in a certain region dropped by 28% last year to a rate of 500 crimes per 100,000 citizens, what was the approximate rate before the drop?

A. 500 crimes per 128,000 citizens

B. 640 crimes per 128,000 citizens

C. 695 crimes per 128,000 citizens

D. 640 crimes per 100,000 citizens

E. 695 crimes per 100,000 citizens



Let us keep the citizens as same 100,000 as the choices have either 100,000 or 128,000.
We would look at 128,000 if the choices with 100,000 don't fit in.
If the citizens are same, only the numerator 500 will get affected...
28% drop means 72% of initial, so initial = \(\frac{500*100}{72}\)... Now this should be > \(\frac{500*100}{75}\) or \(\frac{500*4}{3}=666.7\).
Only E fits in..
If we lo0K at A, B and C , the numerator should be ore than 695 as the denominator has been increased.
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Re: If the crime rate in a certain region dropped by 28% last year to a ra  [#permalink]

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New post 09 Apr 2019, 02:44
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AkshdeepS wrote:
If the crime rate in a certain region dropped by 28% last year to a rate of 500 crimes per 100,000 citizens, what was the approximate rate before the drop?

A. 500 crimes per 128,000 citizens

B. 640 crimes per 128,000 citizens

C. 695 crimes per 128,000 citizens

D. 640 crimes per 100,000 citizens

E. 695 crimes per 100,000 citizens


earlier rate x
and drop 28% = .72
so x*0.72 = 500/10^5
x= ~695 per 10^5
IMO E
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Re: If the crime rate in a certain region dropped by 28% last year to a ra   [#permalink] 09 Apr 2019, 02:44
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