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If the given addition is correct, what is the sum of T, U and V?

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If the given addition is correct, what is the sum of T, U and V?  [#permalink]

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New post 29 Sep 2018, 10:47
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16% (02:34) correct 84% (03:00) wrong based on 113 sessions

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PS + QS + RS = TUV

If the given addition is correct, what is the sum of T, U and V? (P, Q, R, S, T, U and V are distinct digits.)

(1) P, Q and R are consecutive odd integers.

(2) T = 2

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Re: If the given addition is correct, what is the sum of T, U and V?  [#permalink]

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New post 29 Sep 2018, 23:11

Official Solution:



Statement 1:
This statement yields three possibilities for P, Q, and R, in some order: {1, 3, 5}, {3, 5, 7}, {5, 7, 9}; it makes no difference which of P, Q, and R is which digit, because they are all added together.
• If P, Q, and R are 1, 3, and 5 (in whatever order), then the digit T must be 1. This means the digits aren't distinct, so it is impossible.
• If P, Q, and R are 3, 5, and 7 (in whatever order), then T= I. That means S is one of the leftover digits O, 2, 4 6, 8, 9. If these values are plugged into S one at a time, the only one that yields all distinct digits is S -4 (34 + 54+74=162).
• If P, Q, and R are 5, 7, and 9 (in whatever order), then T = 2. That means S is one of the leftover digits O, 1, 3, 4, 6, 8. If these values are plugged into S one at a time, the only one that yields all distinct digits is S = 8 (58 + 78 + 98 = 234).
• Therefore, there are only two possible values of TUV: 162 and 234. In both cases, the sum of T, U, and V is 9,
so (I) is sufficient.

Statement 2:
If T = 2, then trial and error will yield a number of working sets of digits yielding different values for TUV. Examples: 58 + 68 + 78 = 204 (T+ U + V = 6); 41 + 71 + 91 203 ( T+ U + V = 5); 49+69 +89 207 (T+ U + V = 9); and several others.
Therefore, (2) is insufficient.

Answer A


gmatbusters wrote:

Weekly Quant Quiz Question -10


If the given addition is correct, what is the sum of T, U and V?
P, Q, R, S, T, U and V are distinct digits.


Attachment:
Gmatbusters Quiz -2.jpeg



a) P, Q and R are consecutive odd integers.
b) T = 2


ONLY THE TEXT SOLUTIONS ARE ALLOWED


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If the given addition is correct, what is the sum of T, U and V?  [#permalink]

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New post 04 Mar 2019, 07:30
1
Recheck your assumption, All P, Q, R, S, T, U, V are distinct.

As per your assumption:

" TUV P, Q, R can be (3,5,7)

S can be 2

Then it will yield 156,

HERE: U and Q both are 5, but these should be distinct
[/color]

hence assumption is invalid.

"

PearlRay wrote:

Official Solution:



Statement 1:
This statement yields three possibilities for P, Q, and R, in some order: {1, 3, 5}, {3, 5, 7}, {5, 7, 9}; it makes no difference which of P, Q, and R is which digit, because they are all added together.
• If P, Q, and R are 1, 3, and 5 (in whatever order), then the digit T must be 1. This means the digits aren't distinct, so it is impossible.
• If P, Q, and R are 3, 5, and 7 (in whatever order), then T= I. That means S is one of the leftover digits O, 2, 4 6, 8, 9. If these values are plugged into S one at a time, the only one that yields all distinct digits is S -4 (34 + 54+74=162).
• If P, Q, and R are 5, 7, and 9 (in whatever order), then T = 2. That means S is one of the leftover digits O, 1, 3, 4, 6, 8. If these values are plugged into S one at a time, the only one that yields all distinct digits is S = 8 (58 + 78 + 98 = 234).
• Therefore, there are only two possible values of TUV: 162 and 234. In both cases, the sum of T, U, and V is 9,
so (I) is sufficient.

Statement 2:
If T = 2, then trial and error will yield a number of working sets of digits yielding different values for TUV. Examples: 58 + 68 + 78 = 204 (T+ U + V = 6); 41 + 71 + 91 203 ( T+ U + V = 5); 49+69 +89 207 (T+ U + V = 9); and several others.
Therefore, (2) is insufficient.

Answer A


gmatbusters wrote:

Weekly Quant Quiz Question -10


If the given addition is correct, what is the sum of T, U and V?
P, Q, R, S, T, U and V are distinct digits.


Attachment:
Gmatbusters Quiz -2.jpeg



a) P, Q and R are consecutive odd integers.
b) T = 2


ONLY THE TEXT SOLUTIONS ARE ALLOWED



P Q R (3,5,7) s = (2) TUV = 156
Why 32 + 52 + 72 = 156 is not unique?[/quote]

gmatbusters

This is a possibility as per statement 1 only.

TUV can be (3,5,7)

S can be 2

Then it will yield 156

But 1+5+6=11 ! not 9. Please help[/quote]
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Re: If the given addition is correct, what is the sum of T, U and V?  [#permalink]

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New post 29 Sep 2018, 10:56
Consider A, P Q R are consecutive odd integers. For any sets 1,3,5; 5,7,9; 3,5,7 depending on S values, sum of T, U, V varies.

A is not sufficient.

Consider B, if T = 2, P, Q ,R could be any distinct digits and S can vary giving different values for sum of T,U,V. Hence, B is insufficient.

Combine A,B, if T = 2 then P, Q, R must be 5,7,9 in any order and S must be 8 to satisfy the distinct digits condition giving a unique sum of T,U,V to be 2 + 3 +4 = 5

Answer C.
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Re: If the given addition is correct, what is the sum of T, U and V?  [#permalink]

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New post 29 Sep 2018, 10:57
Answer is E

As per 1) we know the numbers in 10s digit are odd consecutive integers...But this enough is not suffieicient...it can be either 3,5,7 or 5,7,1
As per 2) T=2 . Now this alone does not give any surity. As there can be multiple combinations leading to this

Using Both We know that P,q,R can only be 5,7,1 as any other combination wont give T=2. But still S can take any value and there can be multiple answers.

Hence neither of the statements alone or together are sufficient. Hence the answer is E
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Re: If the given addition is correct, what is the sum of T, U and V?  [#permalink]

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New post 29 Sep 2018, 10:58
1) insufficient
if s=1 then v=3
letting p, q and r = 5,7 and 9 respectively then t=2 and u=1
sum of t, u and v= 6
but if we assume s= 2
v=8 and now the sum is 11
2) we do not have to prove this one as when we consider 1st equation, the value of T is 2 in both the cases
therefore insufficient
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Re: If the given addition is correct, what is the sum of T, U and V?  [#permalink]

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New post 29 Sep 2018, 11:01
PS
QS
RS
____
TUV

If the given addition is correct, what is the sum of T, U and V?
P, Q, R, S, T, U and V are distinct digits.

a) P, Q and R are consecutive odd integers.
P,Q,R=1,3,5 OR 3,5,7 OR 5,7,9
NOT SUFFICIENT

b) T = 2

THEREFORE THE ANSWER BETWEEN 200 AND 298
P,Q,R COULD BE 6,7,8 OR 7,8,9 NOT SUFFICIENT
BOTH TOGETHE NOT SUFFICIENT
ANSWER=E
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Re: If the given addition is correct, what is the sum of T, U and V?  [#permalink]

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New post Updated on: 29 Sep 2018, 11:05
First of all lets note that P,Q,R,S,T,U,V are all distinct digits.

St 1) P Q R are consecutive odd integers - this does not give us any information about TUV as PQR could be 1,3,5 or 3,5,7 or 5,7,9. Hence St 1. by itself is not sufficient

St 2) T = 2. Not sufficient by itself as many possibilities

We are left with tow options either C or E.

Option (C) is correct as a couple of trial and errors shows 234 is TUV and the whole set-up is 58+78+98 = 234

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Originally posted by Gladiator59 on 29 Sep 2018, 11:01.
Last edited by Gladiator59 on 29 Sep 2018, 11:05, edited 1 time in total.
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Re: If the given addition is correct, what is the sum of T, U and V?  [#permalink]

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New post 29 Sep 2018, 11:03
E - both not sufficient
a. It can be any consecutive numbers (not sufficient)
b. T = 2 - not sufficient as the previous three numbers -P Q R-can either be (5,7,9 or 7,9,11)

combined S can be 1 or 2 and V = 3 or 6
and P Q R-can either be (5,7,9 or 7,9,11). Still not sufficient
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Re: If the given addition is correct, what is the sum of T, U and V?  [#permalink]

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New post 29 Sep 2018, 11:09
IMO C

1) NS = possible valid combinations for P,Q.R are (1,3,5) & (5,7,9)
2) Clearly NS
1+2) (5,7,) is valid.......Ans C
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Re: If the given addition is correct, what is the sum of T, U and V?  [#permalink]

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New post 29 Sep 2018, 13:00
A. PQR are consecutive odd integers . Here. S is not given and PQR can be any combination - 1,3,5 or 3,5,7, each set yielding different results. Hence, not sufficient.

B not sufficient as information about other digits not given

Both,

As T =2, PQR will be 5,7,9 (any order)

However S is not given which will impact the value of U and V. Thus both together are not sufficient.

Thus, answer is E

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Re: If the given addition is correct, what is the sum of T, U and V?  [#permalink]

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New post 30 Sep 2018, 11:24
gmatbusters wrote:

Official Solution:



Statement 1:
This statement yields three possibilities for P, Q, and R, in some order: {1, 3, 5}, {3, 5, 7}, {5, 7, 9}; it makes no difference which of P, Q, and R is which digit, because they are all added together.
• If P, Q, and R are 1, 3, and 5 (in whatever order), then the digit T must be 1. This means the digits aren't distinct, so it is impossible.
• If P, Q, and R are 3, 5, and 7 (in whatever order), then T= I. That means S is one of the leftover digits O, 2, 4 6, 8, 9. If these values are plugged into S one at a time, the only one that yields all distinct digits is S -4 (34 + 54+74=162).
• If P, Q, and R are 5, 7, and 9 (in whatever order), then T = 2. That means S is one of the leftover digits O, 1, 3, 4, 6, 8. If these values are plugged into S one at a time, the only one that yields all distinct digits is S = 8 (58 + 78 + 98 = 234).
• Therefore, there are only two possible values of TUV: 162 and 234. In both cases, the sum of T, U, and V is 9,
so (I) is sufficient.

Statement 2:
If T = 2, then trial and error will yield a number of working sets of digits yielding different values for TUV. Examples: 58 + 68 + 78 = 204 (T+ U + V = 6); 41 + 71 + 91 203 ( T+ U + V = 5); 49+69 +89 207 (T+ U + V = 9); and several others.
Therefore, (2) is insufficient.

Answer A


gmatbusters wrote:

Weekly Quant Quiz Question -10


If the given addition is correct, what is the sum of T, U and V?
P, Q, R, S, T, U and V are distinct digits.


Attachment:
Gmatbusters Quiz -2.jpeg



a) P, Q and R are consecutive odd integers.
b) T = 2


ONLY THE TEXT SOLUTIONS ARE ALLOWED



P Q R (3,5,7) s = (2) TUV = 156
Why 32 + 52 + 72 = 156 is not unique?
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Re: If the given addition is correct, what is the sum of T, U and V?  [#permalink]

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New post 30 Sep 2018, 11:32
Hi
We need to find sum of T, U and V
As per your solution, sum of T, U,V = 1+5+6 =12
Where as official solutions gives the sum = 5 , 6...
Since we are getting more than one value of sum, the sum of T, U and V cannot be find uniquely.
Statement 2 is INSUFFICIENT.

Hope it is clear now.

saban wrote:
gmatbusters wrote:

Official Solution:



Statement 1:
This statement yields three possibilities for P, Q, and R, in some order: {1, 3, 5}, {3, 5, 7}, {5, 7, 9}; it makes no difference which of P, Q, and R is which digit, because they are all added together.
• If P, Q, and R are 1, 3, and 5 (in whatever order), then the digit T must be 1. This means the digits aren't distinct, so it is impossible.
• If P, Q, and R are 3, 5, and 7 (in whatever order), then T= I. That means S is one of the leftover digits O, 2, 4 6, 8, 9. If these values are plugged into S one at a time, the only one that yields all distinct digits is S -4 (34 + 54+74=162).
• If P, Q, and R are 5, 7, and 9 (in whatever order), then T = 2. That means S is one of the leftover digits O, 1, 3, 4, 6, 8. If these values are plugged into S one at a time, the only one that yields all distinct digits is S = 8 (58 + 78 + 98 = 234).
• Therefore, there are only two possible values of TUV: 162 and 234. In both cases, the sum of T, U, and V is 9,
so (I) is sufficient.

Statement 2:
If T = 2, then trial and error will yield a number of working sets of digits yielding different values for TUV. Examples: 58 + 68 + 78 = 204 (T+ U + V = 6); 41 + 71 + 91 203 ( T+ U + V = 5); 49+69 +89 207 (T+ U + V = 9); and several others.
Therefore, (2) is insufficient.

Answer A


gmatbusters wrote:

Weekly Quant Quiz Question -10


If the given addition is correct, what is the sum of T, U and V?
P, Q, R, S, T, U and V are distinct digits.


Attachment:
Gmatbusters Quiz -2.jpeg



a) P, Q and R are consecutive odd integers.
b) T = 2


ONLY THE TEXT SOLUTIONS ARE ALLOWED



P Q R (3,5,7) s = (2) TUV = 156
Why 32 + 52 + 72 = 156 is not unique?

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Re: If the given addition is correct, what is the sum of T, U and V?  [#permalink]

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New post 04 Mar 2019, 01:26
saban wrote:
gmatbusters wrote:

Official Solution:



Statement 1:
This statement yields three possibilities for P, Q, and R, in some order: {1, 3, 5}, {3, 5, 7}, {5, 7, 9}; it makes no difference which of P, Q, and R is which digit, because they are all added together.
• If P, Q, and R are 1, 3, and 5 (in whatever order), then the digit T must be 1. This means the digits aren't distinct, so it is impossible.
• If P, Q, and R are 3, 5, and 7 (in whatever order), then T= I. That means S is one of the leftover digits O, 2, 4 6, 8, 9. If these values are plugged into S one at a time, the only one that yields all distinct digits is S -4 (34 + 54+74=162).
• If P, Q, and R are 5, 7, and 9 (in whatever order), then T = 2. That means S is one of the leftover digits O, 1, 3, 4, 6, 8. If these values are plugged into S one at a time, the only one that yields all distinct digits is S = 8 (58 + 78 + 98 = 234).
• Therefore, there are only two possible values of TUV: 162 and 234. In both cases, the sum of T, U, and V is 9,
so (I) is sufficient.

Statement 2:
If T = 2, then trial and error will yield a number of working sets of digits yielding different values for TUV. Examples: 58 + 68 + 78 = 204 (T+ U + V = 6); 41 + 71 + 91 203 ( T+ U + V = 5); 49+69 +89 207 (T+ U + V = 9); and several others.
Therefore, (2) is insufficient.

Answer A


gmatbusters wrote:

Weekly Quant Quiz Question -10


If the given addition is correct, what is the sum of T, U and V?
P, Q, R, S, T, U and V are distinct digits.


Attachment:
Gmatbusters Quiz -2.jpeg



a) P, Q and R are consecutive odd integers.
b) T = 2


ONLY THE TEXT SOLUTIONS ARE ALLOWED



P Q R (3,5,7) s = (2) TUV = 156
Why 32 + 52 + 72 = 156 is not unique?


gmatbusters

This is a possibility as per statement 1 only.

TUV can be (3,5,7)

S can be 2

Then it will yield 156

But 1+5+6=11 ! not 9. Please help
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Re: If the given addition is correct, what is the sum of T, U and V?  [#permalink]

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New post 05 Mar 2019, 05:49
gmatbusters wrote:
Recheck your assumption, All P, Q, R, S, T, U, V are distinct.

As per your assumption:

" TUV P, Q, R can be (3,5,7)

S can be 2

Then it will yield 156,

HERE: U and Q both are 5, but these should be distinct
[/color]

hence assumption is invalid.

"

PearlRay wrote:

Official Solution:



Statement 1:
This statement yields three possibilities for P, Q, and R, in some order: {1, 3, 5}, {3, 5, 7}, {5, 7, 9}; it makes no difference which of P, Q, and R is which digit, because they are all added together.
• If P, Q, and R are 1, 3, and 5 (in whatever order), then the digit T must be 1. This means the digits aren't distinct, so it is impossible.
• If P, Q, and R are 3, 5, and 7 (in whatever order), then T= I. That means S is one of the leftover digits O, 2, 4 6, 8, 9. If these values are plugged into S one at a time, the only one that yields all distinct digits is S -4 (34 + 54+74=162).
• If P, Q, and R are 5, 7, and 9 (in whatever order), then T = 2. That means S is one of the leftover digits O, 1, 3, 4, 6, 8. If these values are plugged into S one at a time, the only one that yields all distinct digits is S = 8 (58 + 78 + 98 = 234).
• Therefore, there are only two possible values of TUV: 162 and 234. In both cases, the sum of T, U, and V is 9,
so (I) is sufficient.

Statement 2:
If T = 2, then trial and error will yield a number of working sets of digits yielding different values for TUV. Examples: 58 + 68 + 78 = 204 (T+ U + V = 6); 41 + 71 + 91 203 ( T+ U + V = 5); 49+69 +89 207 (T+ U + V = 9); and several others.
Therefore, (2) is insufficient.

Answer A


gmatbusters wrote:

Weekly Quant Quiz Question -10


If the given addition is correct, what is the sum of T, U and V?
P, Q, R, S, T, U and V are distinct digits.


Attachment:
Gmatbusters Quiz -2.jpeg



a) P, Q and R are consecutive odd integers.
b) T = 2


ONLY THE TEXT SOLUTIONS ARE ALLOWED



P Q R (3,5,7) s = (2) TUV = 156
Why 32 + 52 + 72 = 156 is not unique?


gmatbusters

This is a possibility as per statement 1 only.

TUV can be (3,5,7)

S can be 2

Then it will yield 156

But 1+5+6=11 ! not 9. Please help[/quote][/quote]

P,Q,R,S,T,U,V all are unique values.
P Q R (3,5,7) s = (2) TUV = 156
Here, Q=U=5 thus not a valid selection.
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Re: If the given addition is correct, what is the sum of T, U and V?  [#permalink]

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New post 12 Mar 2019, 09:24
On my second go, I somehow didn't take the PS, QS, RS as two digit numbers at all. Rather I considered them to be product of the digits. How can we rule out my possibility with nothing given in the question?
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Re: If the given addition is correct, what is the sum of T, U and V?   [#permalink] 12 Mar 2019, 09:24
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