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If the last 6 digits of 1*2*3*4*...*N are zero, what is the

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Joined: 20 Feb 2006
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If the last 6 digits of 1*2*3*4*...*N are zero, what is the [#permalink]

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14 Sep 2006, 09:30
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If the last 6 digits of 1*2*3*4*...*N are zero, what is the least value of N?
A 20 B25 C30 D35.E 40
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Joined: 05 Jul 2006
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14 Sep 2006, 10:27
If the last 6 digits of 1*2*3*4*...*N are zero, what is the least value of N?
A 20 B25 C30 D35.E 40

N! CAN BE EXPRESSED AS = Q*10^6 WHERE Q IS AN INTIGER NOT ENDING IN ZERO

thus to have 10^6 = (5*2)^6 we need five multiples of 5 and sure then we ll have our 2^6

if we divided 30/5 then we will get 6 multoples of 5 namely(5,10,15....30)

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Re: PS Number - quick solution?? [#permalink]

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14 Sep 2006, 13:16
If the last 6 digits of 1*2*3*4*...*N are zero, what is the least value of N?
A 20 B25 C30 D35.E 40

yezz is too smart for me.

I just tried to get tens wherever I could.

2*5=10
10 = 10
4*15 = 60
20 = 20

not enough at 20

25*8=200

that gives us 6 zeroes.

B. 25
Re: PS Number - quick solution??   [#permalink] 14 Sep 2006, 13:16
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