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Re: If the points (a, 0) , (0, b) and (1, 1) are collinear, what is the va [#permalink]
My approach was formula based and it saved my time:
There are three equations of a line
1. y=mx+c

2. Y-y1/X-x1 = y2-y1/x2-x1

3. X/x intercept +Y/ y intercept =1

for this question I am using 3rd equation
since, (a, 0) , (0, b) are nothing but x and y intercept
so, 1/a + 1/b = 1

Hope it helps. Correct me if needed
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Re: If the points (a, 0) , (0, b) and (1, 1) are collinear, what is the va [#permalink]
Draw it on the graph... it will be a line with negative slope intersecting y at b and x at a.
Therefore, eq. Would be x/a + y/b = 1.
Put (1,1) in the above eq. And there u have it!!!

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Re: If the points (a, 0) , (0, b) and (1, 1) are collinear, what is the va [#permalink]
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Points are collinear: Suppose (0,b) is mid-point of other two-points.

=> \(\frac{(a + 1) }{ 2} =0\) and \(\frac{(0 + 1) }{ 2} = b\)

=> a = -1 and b = \(\frac{1}{2}\)

=> \(\frac{1}{a} + \frac{1}{b}\) = -1 + 2 = 1

Answer C
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Re: If the points (a, 0) , (0, b) and (1, 1) are collinear, what is the va [#permalink]
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