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If the roots of the equation 12x^2 - px +5 = 0 is in the

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If the roots of the equation 12x^2 - px +5 = 0 is in the [#permalink]

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30 Jan 2004, 19:31
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If the roots of the equation 12x^2 - px +5 = 0 is in the ratio of 3:2 find the value of p.

a. 5sqrt10
b. 5
c. 5sqrt2
d. 5sqrt3

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30 Jan 2004, 19:41

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30 Jan 2004, 19:45
oops its A) 5sqrt 10

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30 Jan 2004, 19:48
and tommorow we do inequalities
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30 Jan 2004, 19:53
Hey Sunni have u ever tried answering questions after this and this , I am sure it would be this . Ha ha, hope everybody is enjoying the weekend

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30 Jan 2004, 20:34
Bhai, please check ur private message. OK time for sleep

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30 Jan 2004, 20:50
roots are a and b for equation
12x^2-px+5 or x^2-x * p/12 + 5/12
so
1) a+b = p/12
2) ab = 5/12
3) we also know that a/b = 3/2
from 2) and 3) b = sqrt(5/18) and a = sqrt(5/8)

Use Eq 1 and you will get p = 5sqrt(10)

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30 Jan 2004, 20:50
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