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If the side of a square is increased by 25% then its area is increase
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Bunuel
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If the side of a square is increased by 25% then its area is increase [#permalink] New post  01 Jul 2022, 06:15
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If the side of a square is increased by 25% then its area is increased by:

(A) 25%
(B) 40.5%
(C) 55%
(D) 56.25%
(E) 60%
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Re: If the side of a square is increased by 25% then its area is increase [#permalink] New post  01 Jul 2022, 06:32
Bunuel wrote:
If the side of a square is increased by 25% then its area is increased by:

(A) 25%
(B) 40.5%
(C) 55%
(D) 56.25%
(E) 60%

\(25+25+\)\(\frac{25*25}{100}\)
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Re: If the side of a square is increased by 25% then its area is increase [#permalink] New post  01 Jul 2022, 07:39
TECHINIQUE of plug in numbers
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ThatDudeKnows
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Re: If the side of a square is increased by 25% then its area is increase [#permalink] New post  01 Jul 2022, 08:07
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Bunuel wrote:
If the side of a square is increased by 25% then its area is increased by:

(A) 25%
(B) 40.5%
(C) 55%
(D) 56.25%
(E) 60%


Original square: 4x4. Area = 16.
Larger square: 5x5. Area = 25.

9/16 = 1/2 + 1/16
1/16 = half of 1/8, so half of 12.5% = 6.25%
56.25%

Answer choice D.


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If the side of a square is increased by 25% then its area is increase [#permalink] New post  01 Jul 2022, 11:56
ThatDudeKnows wrote:
Bunuel wrote:
If the side of a square is increased by 25% then its area is increased by:

(A) 25%
(B) 40.5%
(C) 55%
(D) 56.25%
(E) 60%


Original square: 4x4. Area = 16.
Larger square: 5x5. Area = 25.

9/16 = 1/2 + 1/16
1/16 = half of 1/8, so half of 12.5% = 6.25%
56.25%

Answer choice D.


ThatDudeKnowsPluggingIn


Very good explanation. I would add;

[(25 - 16)/16]x100 = (9/16) x 100 = 56.25%

Percent change = [(final - initial)/initial] x 100
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If the side of a square is increased by 25% then its area is increase [#permalink]
01 Jul 2022, 11:56
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