sidinsin wrote:

HI

For St A:

We could have the numbers as: (x)+(x+1)+(x+2)+(x+3)+(x+4)+(x+5)=875 or (x-2)+(x-1)+x+(x+1)+(x+2)=875. In either case, the value of X will be different.

For St B:

Not Suff

A+B: Not Suff

Thus, IMO the answer should be E

No, that's not correct.

First of all, it should be (x)+(x+1)+(x+2)+(x+3)+(x+4)=875 (we have 5 terms not 6) --> x =

173.

Next, notice that x in my solution is the third term while in yours it's the first. From my solution x=175, so the first term is

173. As you can see the sequence is the same in both cases: {173, 174, 175, 176, 177}.

You will get the same result if you denote the 5th, or any other term by x.

Anyway, you could avoid all this calculations if you understand the second approach given there: there can be only one set of five consecutive integers which add up to 875, so the sequence is fixed and thus its each term can be found.

Hope it's clear.

_________________

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