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If the sum of four consecutive even integers is 340, then the average

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Bunuel
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If the sum of four consecutive even integers is 340, then the average [#permalink] New post   06 Feb 2019, 02:59
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If the sum of four consecutive even integers is 340, then the average of the two larger integers is

A. 83
B. 85
C. 86
D. 87
E. 88
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D
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Re: If the sum of four consecutive even integers is 340, then the average [#permalink] New post   06 Feb 2019, 03:04
Bunuel wrote:
If the sum of four consecutive even integers is 340, then the average of the two larger integers is

A. 83
B. 85
C. 86
D. 87
E. 88



x + x + 2 + x + 4 + x + 6 = 340

4x + 12 = 340

4x = 328

x = 82.

3rd = 86

4th = 88

Average must be 87.

D is the correct answer.
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Re: If the sum of four consecutive even integers is 340, then the average [#permalink] New post   06 Feb 2019, 03:17
4 consecutive integers can be written as 2n, 2n+2, 2n+4, 2n+6

Given
2n + 2n+2 + 2n+4 + 2n+6 = 340

To find
(2n+4 + 2n+6)/2

Solution

8n+12=340
Thus n = 41

(2n+4 + 2n+6)/2 can be simplified to (4n+10)2

Substitute n as 41 we get 87

(D)

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Re: If the sum of four consecutive even integers is 340, then the average [#permalink] New post   06 Feb 2019, 06:31
Bunuel wrote:
If the sum of four consecutive even integers is 340, then the average of the two larger integers is

A. 83
B. 85
C. 86
D. 87
E. 88


x+x+2+x+4+x+6= 340
4x+12= 340
x= 82

avg of two large integers = 86+88/2 = 87
IMO D
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Re: If the sum of four consecutive even integers is 340, then the average [#permalink]
06 Feb 2019, 06:31
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