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Any number evenly divisible by 8 must also be evenly divisible by 4. An integer is divisible by 4 if and only if its last two digits are a multiple of 4. 22, 42, and 62 are not divisible by 4. This leaves only Choices (B) and (D), so try dividing 532 by 8: 532 + 8 does not divide evenly, so the answer must be (D), 552

Hi, I want to know whether we can solve this without plugging the number in W, please. I plugged in different numbers before I found the right answer...

If the three-digit number 5W2 is evenly divisible by 8, which of the following could be the digit W ?

A. 2 B. 3 C. 4 D. 5 E. 6

OE Any number evenly divisible by 8 must also be evenly divisible by 4. An integer is divisible by 4 if and only if its last two digits are a multiple of 4. 22, 42, and 62 are not divisible by 4. This leaves only Choices (B) and (D), so try dividing 532 by 8: 532 + 8 does not divide evenly, so the answer must be (D), 552.

Hi, I want to know whether we can solve this without plugging the number in W, please. I plugged in different numbers before I found the right answer...

I'd solve this question the same way as in OE. Think it the easiest solution.
_________________

Re: If the three-digit number 5W2 is evenly divisible by 8, [#permalink]

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18 Feb 2014, 21:58

If the three-digit number 5W2 is evenly divisible by 8, which of the following could be the digit W ?

A. 2 B. 3 C. 4 D. 5 E. 6

Given that, the three digit number 5W2 is divisible by 8, then using the divisibility rule, that is 8 is divisible by the number if sum of four times the hundreds digit, twice the tens digit and units digit of the number is divisible by 8. Or, 4 * 5 + 2 * W + 1 * 2 = 22 + 2W is divisible by 8 Or, W can be 1, 5, 9......