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# If w+x<0, is w-y>0?

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Joined: 22 Aug 2013
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Re: If w+x<0, is w-y>0?  [#permalink]

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07 Jun 2018, 00:03
ganesh999 wrote:
Bunuel wrote:
gmatbull wrote:
If w + x < 0, is w - y . 0?
(1) x + y < 0
(2) y < x < w

I don't know why i missed this question; with regards to (1)

If w + x < 0 , is w - y > 0 ?

Question: is $$w>y$$?

(1) x + y < 0 --> for this statement best way would be to pick numbers: on DS questions when plugging numbers, goal is to prove that the statement is not sufficient. So we should try to get a YES answer with one chosen number(s) and a NO with another.

If $$x=0$$, $$w=-1$$ and $$y=-2$$ then the answer would be YES but if $$x=0$$, $$w=-2$$ and $$y=-1$$ then the answer would be. Not sufficient.

(2) $$y<x<w$$ --> ignore $$x$$ --> $$y<w$$, directly tells us the answer. Sufficient.

Hello Buneul,
I'm struck with the following approach.

For the condition w > y to hold,
I undertook the following approach.

w + x < 0 , w - y > 0
I subtracted both of them
I got x + y < 0.
So i deduced that for w - y > 0 to hold, we need the condition x + y < 0, condition that is present in the answer choice.
and hence I wrote D as the answer.
Am I missing something?

Hello

See, the thing is that you are assuming w-y to be > 0.
The catch here is that IF w+x < 0 and also IF w-y > 0, THEN x+y < 0.

BUT it does NOT mean that IF w+x < 0 and IF x+y < 0, then w-y will be > 0.
Eg, consider w=-4, x=-5, y=-3. Here w+x is negative and x+y is negative, but w-y is not greater than 0, rather w is less than y here.
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Re: If w+x<0, is w-y>0?  [#permalink]

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20 Jun 2019, 00:05
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Re: If w+x<0, is w-y>0?   [#permalink] 20 Jun 2019, 00:05

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