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If x ≥ 0, (0.49x^16)^(1/2) then must be equal to

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Joined: 02 Sep 2009
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If x ≥ 0, (0.49x^16)^(1/2) then must be equal to  [#permalink]

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28 Oct 2018, 23:39
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Difficulty:

15% (low)

Question Stats:

72% (00:43) correct 28% (00:42) wrong based on 75 sessions

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If x ≥ 0, $$\sqrt{0.49x^{16}}$$ then must be equal to

A. $$0.07x^8$$

B. $$0.07x^4$$

C. $$0.7x^{14}$$

D. $$0.7x^8$$

E. $$0.7x^4$$

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If x ≥ 0, (0.49x^16)^(1/2) then must be equal to  [#permalink]

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Updated on: 29 Oct 2018, 22:40
$$\sqrt{0.49x^{16}}$$ = $$\sqrt{49/100}*x^8$$ = $$\frac{7}{10}*x^8$$ = $$0.7x^8$$

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Originally posted by Chethan92 on 29 Oct 2018, 00:56.
Last edited by Chethan92 on 29 Oct 2018, 22:40, edited 1 time in total.
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Re: If x ≥ 0, (0.49x^16)^(1/2) then must be equal to  [#permalink]

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29 Oct 2018, 22:28
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√0.49x^16 = 0.7* x^8

( 0.7*0.7=0.49 & since x appears 16 times or rather is multiplied 16 times taking the square root of those 16 X'es will give us half of it i.e 8)

Please give kudos if you liked my explanation.
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Re: If x ≥ 0, (0.49x^16)^(1/2) then must be equal to   [#permalink] 29 Oct 2018, 22:28
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