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If x<0 and 0<(x/y)+1<1, which of the following must

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SVP
Joined: 24 Aug 2006
Posts: 2130
Followers: 3

Kudos [?]: 144 [0], given: 0

If x<0 and 0<(x/y)+1<1, which of the following must [#permalink]

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11 Nov 2006, 21:11
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If x<0 and 0<(x/y)+1<1, which of the following must be true?

I. y>0

II. (x/y)>-1

III. (1/x) + (1/y) < 0

I only
I and II only
I and III only
II and III only
I, II and III
Manager
Joined: 03 Nov 2006
Posts: 161
Followers: 2

Kudos [?]: 4 [0], given: 0

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11 Nov 2006, 23:14
I'm going for E here.
Current Student
Joined: 29 Jan 2005
Posts: 5222
Followers: 26

Kudos [?]: 402 [0], given: 0

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12 Nov 2006, 06:35
x must be less than y for the stem to hold. (E) wins here.
SVP
Joined: 05 Jul 2006
Posts: 1747
Followers: 6

Kudos [?]: 358 [0], given: 49

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12 Nov 2006, 06:36
If x<0 and 0<(x/y)+1<1, which of the following must be true?

I. y>0

II. (x/y)>-1

III. (1/x) + (1/y) < 0

I only I and II only I and III only II and III only I , II and III.

X is -ve

-1< x/y< 0 therfore x/y is -ve fraction

x is -ve thus y is +ve

the three are valid must
VP
Joined: 28 Mar 2006
Posts: 1372
Followers: 2

Kudos [?]: 33 [0], given: 0

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12 Nov 2006, 12:34
If x<0 and 0<(x/y)+1<1, which of the following must be true?

I. y>0

II. (x/y)>-1

III. (1/x) + (1/y) < 0

From the stem if (x/y)+1 is between 0 and 1 then it is a fraction between 0 and 1.

Since x<0 then y>0 so that the (x/y)+1 is a value between 0 and 1.

So 1) and 2 are true

(1/x) + (1/y) < 0 means x+y <0 which is also correct

12 Nov 2006, 12:34
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