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Re: If x≠0 and x = (4xy-4y^2)^1/2, then, in terms of y, x = [#permalink]

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26 Mar 2011, 07:49

1

This post received KUDOS

@petrifiedbutstanding:-

Well it means : Squaring we get: x^2 =4y(x-y) Assume X^2=m >>>>>>>>>>>1 Than ,m=4y(m^1/2-y) on solving:m-4y(m)^1/2+4y^2=0 >> quadratic in y s solve for y. Y comes out to be =(m^1/2)/2

Re: If x≠0 and x = (4xy-4y^2)^1/2, then, in terms of y, x = [#permalink]

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18 Jul 2016, 07:04

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