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If x < 0 and y is 5 more than the square of x, which one of the follow

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If x < 0 and y is 5 more than the square of x, which one of the follow [#permalink]

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If x < 0 and y is 5 more than the square of x, which one of the following expresses x in terms of y?

(A) x = \(\sqrt{y − 5}\)
(B) x = −\(\sqrt{y − 5}\)
(C) x = \(\sqrt{y + 5}\)
(D) x = \(\sqrt{y^2 − 5}\)
(E) x = −\(\sqrt{y^2 − 5}\)
[Reveal] Spoiler: OA

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Re: If x < 0 and y is 5 more than the square of x, which one of the follow [#permalink]

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SajjadAhmad wrote:
If x < 0 and y is 5 more than the square of x, which one of the following expresses x in terms of y?

(A) x = \(\sqrt{y − 5}\)
(B) x = −\(\sqrt{y − 5}\)
(C) x = \(\sqrt{y + 5}\)
(D) x = \(\sqrt{y^2 − 5}\)
(E) x = −\(\sqrt{y^2 − 5}\)


Given \(y=5+x^2 => x^2=y-5\)

Hence \(x= ±\sqrt{y-5}\), but as \(x<0\) i.e negative so

\(x =\) −\(\sqrt{y − 5}\)

Option B

Kudos [?]: 304 [1], given: 39

Re: If x < 0 and y is 5 more than the square of x, which one of the follow   [#permalink] 17 Oct 2017, 11:41
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If x < 0 and y is 5 more than the square of x, which one of the follow

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