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# If x < 0 and y is 5 more than the square of x, which one of the follow

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SVP
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If x < 0 and y is 5 more than the square of x, which one of the follow  [#permalink]

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17 Oct 2017, 11:56
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If x < 0 and y is 5 more than the square of x, which one of the following expresses x in terms of y?

(A) x = $$\sqrt{y − 5}$$
(B) x = −$$\sqrt{y − 5}$$
(C) x = $$\sqrt{y + 5}$$
(D) x = $$\sqrt{y^2 − 5}$$
(E) x = −$$\sqrt{y^2 − 5}$$

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Re: If x < 0 and y is 5 more than the square of x, which one of the follow  [#permalink]

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17 Oct 2017, 12:41
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If x < 0 and y is 5 more than the square of x, which one of the following expresses x in terms of y?

(A) x = $$\sqrt{y − 5}$$
(B) x = −$$\sqrt{y − 5}$$
(C) x = $$\sqrt{y + 5}$$
(D) x = $$\sqrt{y^2 − 5}$$
(E) x = −$$\sqrt{y^2 − 5}$$

Given $$y=5+x^2 => x^2=y-5$$

Hence $$x= ±\sqrt{y-5}$$, but as $$x<0$$ i.e negative so

$$x =$$ −$$\sqrt{y − 5}$$

Option B
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Re: If x < 0 and y is 5 more than the square of x, which one of the follow  [#permalink]

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31 May 2018, 00:28
If x < 0 and y is 5 more than the square of x, which one of the following expresses x in terms of y?

(A) x = $$\sqrt{y − 5}$$
(B) x = −$$\sqrt{y − 5}$$
(C) x = $$\sqrt{y + 5}$$
(D) x = $$\sqrt{y^2 − 5}$$
(E) x = −$$\sqrt{y^2 − 5}$$

x < 0 and y = x^2 + 5

$$- x$$ = $$\sqrt{y - 5}$$

$$x$$ = $$-\sqrt{y - 5}$$

(B)
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Re: If x < 0 and y is 5 more than the square of x, which one of the follow  [#permalink]

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01 Jun 2018, 11:24
If x < 0 and y is 5 more than the square of x, which one of the following expresses x in terms of y?

(A) x = $$\sqrt{y − 5}$$
(B) x = −$$\sqrt{y − 5}$$
(C) x = $$\sqrt{y + 5}$$
(D) x = $$\sqrt{y^2 − 5}$$
(E) x = −$$\sqrt{y^2 − 5}$$

We can create the equation:

x^2 + 5 = y

x^2 = y - 5

x =±√(y - 5)

However, since x is negative we have:

x = -√(y - 5)

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Re: If x < 0 and y is 5 more than the square of x, which one of the follow &nbs [#permalink] 01 Jun 2018, 11:24
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