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# If x > 0, how many integer values of (x, y) will satisfy the equation

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Joined: 03 Mar 2018
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If x > 0, how many integer values of (x, y) will satisfy the equation  [#permalink]

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Updated on: 17 Apr 2018, 12:10
1
14
00:00

Difficulty:

95% (hard)

Question Stats:

35% (02:20) correct 65% (02:24) wrong based on 222 sessions

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If x > 0, how many integer values of (x, y) will satisfy the equation 5x + 4|y| = 55?

(A) 3
(B) 6
(C) 5
(D) 4
(E) 2

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Originally posted by itisSheldon on 16 Apr 2018, 03:39.
Last edited by itisSheldon on 17 Apr 2018, 12:10, edited 1 time in total.
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Re: If x > 0, how many integer values of (x, y) will satisfy the equation  [#permalink]

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16 Apr 2018, 04:48
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1
The equation will be
5x +4y =55 , when y > or =0
Considering integer solution, (x,y) can be (3,10),(7,5),(11,0)
5x - 4y =55 , when y<0
Considering integer solutions, (x,y) can be (3,-10),(7,-5)
Hence there will be 5 integral solutions.
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Re: If x > 0, how many integer values of (x, y) will satisfy the equation  [#permalink]

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17 Apr 2018, 10:08
Greetings!
How did u calculate solutions?
gmatbusters wrote:
The equation will be
5x +4y =55 , when y > or =0
Considering integer solution, (x,y) can be (3,10),(7,5),(11,0)
5x - 4y =55 , when y<0
Considering integer solutions, (x,y) can be (3,-10),(7,-5)
Hence there will be 5 integral solutions.
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Joined: 27 Oct 2017
Posts: 1259
Location: India
GPA: 3.64
WE: Business Development (Energy and Utilities)
Re: If x > 0, how many integer values of (x, y) will satisfy the equation  [#permalink]

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17 Apr 2018, 10:27
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1
Please see the sketch for procedure to find the integral solution of a linear equation.
Attachment:

IMG-20180417-WA0066.jpg [ 123.37 KiB | Viewed 2248 times ]

Jahfors wrote:
Greetings!
How did u calculate solutions?
gmatbusters wrote:
The equation will be
5x +4y =55 , when y > or =0
Considering integer solution, (x,y) can be (3,10),(7,5),(11,0)
5x - 4y =55 , when y<0
Considering integer solutions, (x,y) can be (3,-10),(7,-5)
Hence there will be 5 integral solutions.

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If x > 0, how many integer values of (x, y) will satisfy the equation  [#permalink]

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30 Apr 2018, 06:36
1
To get x as intger y need to be multiple of 5
So possible values of y are 0,5,10,15....

But only after and with 15 x becomes -ve but x cannot be negative

So values of y are 0,5,10
Y is |y| so -ve values need to be considered

Total values of y are 0,5,-5,10,-10

With each of these y values x value also comes

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Re: If x > 0, how many integer values of (x, y) will satisfy the equation  [#permalink]

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04 May 2018, 18:03
Good one, I did it using the 'monkey' method, trying x,y numbers...

gmatbusters wrote:
The equation will be
5x +4y =55 , when y > or =0
Considering integer solution, (x,y) can be (3,10),(7,5),(11,0)
5x - 4y =55 , when y<0
Considering integer solutions, (x,y) can be (3,-10),(7,-5)
Hence there will be 5 integral solutions.
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Re: If x > 0, how many integer values of (x, y) will satisfy the equation  [#permalink]

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29 May 2019, 07:48
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Re: If x > 0, how many integer values of (x, y) will satisfy the equation   [#permalink] 29 May 2019, 07:48
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