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# If x^(1/6) = 6, then √x^6 is ?

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If x^(1/6) = 6, then √x^6 is ? [#permalink]

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30 Mar 2012, 18:17
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If x^(1/6) = 6, then √x^6 is ?

A. 6
B. 6√6
C. 6^6
D. 6^18
E. 6^36
[Reveal] Spoiler: OA

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Last edited by Bunuel on 31 Mar 2012, 01:22, edited 1 time in total.
Edited the question
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Re: If x^(1/6) = 6, then √x^6 is ? [#permalink]

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31 Mar 2012, 01:21
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If $$\sqrt[6]{x}= 6$$, then $$\sqrt{x^6}$$ is ?
A. 6
B. 6√6
C. 6^6
D. 6^18
E. 6^36

$$\sqrt[6]{x}= 6$$ --> $$x=6^6$$. So, $$\sqrt{x^6}=x^3=(6^6)^3=6^{18}$$.

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Re: If x^(1/6) = 6, then √x^6 is ? [#permalink]

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31 Mar 2012, 03:11
Thanks , however.

Sometimes I'm intimidated from the question.

For the second part was clear: x^6/3 = x^3 and then substitution.

The first part was so simple.....likewise.

Thanks
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Re: If x^(1/6) = 6, then √x^6 is ? [#permalink]

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01 Apr 2012, 07:11
bunnel

how did you come x=6^6,please explain
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Re: If x^(1/6) = 6, then √x^6 is ? [#permalink]

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01 Apr 2012, 07:20
TomB wrote:
bunnel

how did you come x=6^6,please explain

because to cancel out your root you have to raise the same to the exponent of the same and at the same time raise the other part of the equation.

For instance: if you have √x= 4 rise to power of 2 both side; so you'll have x=16 or 3√x=4 then you'll have x=64 (rise to power of 3).

So we have x=6^6; of course in our case we do not need to obtain 6^6 (46656). we care about to substitute this value to our x and then resolve our problem. It was simple but me too was confused looking at the problem.

I ask to Bunuel to correct me if I'm wrong.
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Last edited by carcass on 01 Apr 2012, 09:23, edited 1 time in total.
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Re: If x^(1/6) = 6, then √x^6 is ? [#permalink]

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01 Apr 2012, 08:38
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TomB wrote:
bunnel

how did you come x=6^6,please explain

$$\sqrt[6]{x}= 6$$ --> raise to the sixth power: $$(\sqrt[6]{x})^6= 6^6$$ --> $$x=6^6$$.

Hope it's clear.
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Re: If x^(1/6) = 6, then √x^6 is ? [#permalink]

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01 Apr 2012, 16:35
Vote for D

this is one to bookmark

x^1/6 = 6

raise the power to 6

x^6/6 = 6^6

therefore

x = 6^6

now

=x^6/2
=x^3
=(6^6)^3
=6^18
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Re: If x^(1/6) = 6, then √x^6 is ? [#permalink]

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29 Apr 2012, 11:15
carcass wrote:
If x^(1/6) = 6, then √x^6 is ?

A. 6
B. 6√6
C. 6^6
D. 6^18
E. 6^36

Ans explanation

x^(1/6) can be written as 6\sqrt{x}

so 6\sqrt{x}=6

by raising to the power of six both sides we get

(6\sqrt{x})^6=6^6

we get x=6^6

\sqrt{x} ^6=(\sqrt{6^6})

(6^6/2)6=(6^3)^6=6^3*6=6^18
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Re: If x^(1/6) = 6, then √x^6 is ? [#permalink]

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05 Jun 2013, 04:28
Bumping for review and further discussion*. Get a kudos point for an alternative solution!

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Re: If x^(1/6) = 6, then √x^6 is ? [#permalink]

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05 Jun 2013, 07:39
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$$\sqrt{x}^6$$ can be rewritten as $$x^3$$
if $$\sqrt[6]{x} = 6$$ and $$(\sqrt[6]{x})^1^8 = x^3$$, then $$x^3 = 6^1^8$$
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Re: If x^(1/6) = 6, then √x^6 is ? [#permalink]

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06 Jun 2013, 07:20
In such cases i always try to find some simple number for which i am sure and make simple but similar calculation.
For example in our case we have x^(1/6)=6 from a glance it is difficult to get what is this number, but if we take $$\sqrt{x}$$=2 we see that x is 4, because x^1/2=2 is the same as to say 2 multiplied by itself once. In our case we have x^(1/6)=6 using our logic that means x=6^6.
In the second expression we have (x^6)^1/2 ---> (x)^6*1/2=x^3

Now the easiest part, since we know that x=6^6 then x^3=(6^6)^3=6^18

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Re: If x^(1/6) = 6, then √x^6 is ? [#permalink]

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26 Feb 2014, 23:29
x^1/6 = 6
We require to find x^3
So power both sides by 18

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Re: If x^(1/6) = 6, then √x^6 is ? [#permalink]

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08 Mar 2014, 10:28
Option D.
X^1/6=6
Therefore x=6^6
Cubing both sides above
We get x^3=6^18

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Re: If x^(1/6) = 6, then √x^6 is ? [#permalink]

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17 May 2015, 12:04
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Re: If x^(1/6) = 6, then √x^6 is ? [#permalink]

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28 Jan 2017, 08:39
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: If x^(1/6) = 6, then √x^6 is ?   [#permalink] 28 Jan 2017, 08:39
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