If x = -1 and n is the sum of the second 101 prime numbers, what is th

There are total 25 prime numbers from 1 to 100
There are total 26 prime numbers from 1 to 101

Now given , " second 101 prime numbers " , I think that prime number starts from 3 to 101 . Excluding 2 [first prime number]

List of second 101 prime numbers are
3,5,7,11,13,17.....101
There are total 25 second 101 primer numbers.

If we can calculate n as even or odd, that will results into the solution as X = -1

Sum of second 2 prime numbers is even
Sum of second 3 prime numbers is odd
Sum of second 4 prime numbers is even
Sum of second 5 prime numbers is odd
.
.
.
.
Sum of second 25 prime numbers is odd

There n is odd.

x^n + x^(n+1) + x^(n+2) + x^(n+3)
is

(-1)^odd + (-1)^(odd + 1) + (-1)^(odd + 2) + (-1)^(odd + 3)

-1 + (-1)^(even) + (-1)^(odd) + (-1)^(even)

-1 + 1 - 1 + 1

0

Answer is C