Given, (x^3-2x^2+x-1)^2-1=(x-a)(x-b)(x-c)(x-d)(x-e)(x-f)

using formula a^2 - b^2 = (a+b)(a-b), we can get

(x^3-2x^2+x-1)^2-1 = (x^3-2x^2+x-1+1)(x^3-2x^2+x-1-1)

= (x^3-2x^2+x)(x^3-2x^2+x-2)

= x(x^2-2x+1)(x^3-2x^2+x-1-1)

No need to solve further, we can see one of the factors of x would be equal to see when the above equation is equated to zero.

Hence, abcdef = 0.

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