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# If x=3/4 and y=2/5, what is the value of sqrt(x^2 + 6x + 9)

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CEO
Joined: 21 Jan 2007
Posts: 2734

Kudos [?]: 1088 [0], given: 4

Location: New York City
If x=3/4 and y=2/5, what is the value of sqrt(x^2 + 6x + 9) [#permalink]

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11 Dec 2007, 13:56
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If x=3/4 and y=2/5, what is the value of sqrt(x^2 + 6x + 9) - sqrt (y^2 -2y + 1)?

87/20
63/20
47/20
15/4
14/5

Kudos [?]: 1088 [0], given: 4

CEO
Joined: 17 Nov 2007
Posts: 3583

Kudos [?]: 4714 [0], given: 360

Concentration: Entrepreneurship, Other
Schools: Chicago (Booth) - Class of 2011
GMAT 1: 750 Q50 V40

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11 Dec 2007, 14:22
B

√(x²+6x+9) - √ (y²-2y+1) = √(x+3)² - √ (y-1)²=|x+3| - |y-1| =

= |3/4+3| - |2/5-1| = 15/4 - 3/5 = (75 - 12)/20 = 63/20

Kudos [?]: 4714 [0], given: 360

11 Dec 2007, 14:22
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# If x=3/4 and y=2/5, what is the value of sqrt(x^2 + 6x + 9)

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