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# If x < −3y/2, is x < 0? (1) y > 0 (2) 2x + 5y = 20

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Math Expert
Joined: 02 Sep 2009
Posts: 58445
If x < −3y/2, is x < 0? (1) y > 0 (2) 2x + 5y = 20  [#permalink]

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01 Nov 2018, 00:23
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Difficulty:

55% (hard)

Question Stats:

56% (02:04) correct 44% (01:55) wrong based on 28 sessions

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If x < −3y/2, is x < 0?

(1) y > 0
(2) 2x + 5y = 20

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NUS School Moderator
Joined: 18 Jul 2018
Posts: 1021
Location: India
Concentration: Finance, Marketing
WE: Engineering (Energy and Utilities)
Re: If x < −3y/2, is x < 0? (1) y > 0 (2) 2x + 5y = 20  [#permalink]

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01 Nov 2018, 01:31
From statement 1:

Y > 0. Y is positive.
-3Y/2 becomes negative.
This means that x is also negative.
Since $$x < -3y/2$$
1 is sufficient.

From statement 2:

2x+5y = 20.
Also, x+3y/2 < 0

2x+3y<0

2x+3y = 20-2y

Then 20-2y<0 or 20<2y

10<y. Y is positive.
Then x<0.
2 is sufficient.

D is the answer.
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Re: If x < −3y/2, is x < 0? (1) y > 0 (2) 2x + 5y = 20   [#permalink] 01 Nov 2018, 01:31
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# If x < −3y/2, is x < 0? (1) y > 0 (2) 2x + 5y = 20

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