If |x – 9/2| = 5/2, and if y is the median of a set of p : GMAT Problem Solving (PS)
Check GMAT Club Decision Tracker for the Latest School Decision Releases https://gmatclub.com/AppTrack

It is currently 24 Feb 2017, 17:06
GMAT Club Tests

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

If |x – 9/2| = 5/2, and if y is the median of a set of p

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:

Hide Tags

4 KUDOS received
Manager
Manager
avatar
Joined: 29 Oct 2009
Posts: 201
Concentration: General Management, Sustainability
WE: Consulting (Computer Software)
Followers: 2

Kudos [?]: 93 [4] , given: 12

If |x – 9/2| = 5/2, and if y is the median of a set of p [#permalink]

Show Tags

New post 18 Apr 2010, 15:27
4
This post received
KUDOS
13
This post was
BOOKMARKED
00:00
A
B
C
D
E

Difficulty:

  65% (hard)

Question Stats:

64% (02:52) correct 36% (01:58) wrong based on 594 sessions

HideShow timer Statistics

If |x – 9/2| = 5/2, and if y is the median of a set of p consecutive integers, where p is odd, which of the following must be true?

I. xyp is odd
II. xy(p^2 + p) is even
III. x^2y^2p^2 is even

A. II only
B. III only
C. I and III
D. II and III
E. I, II, and III
[Reveal] Spoiler: OA

_________________

+1Kudos, if this helps


Last edited by Bunuel on 06 Jul 2013, 11:27, edited 3 times in total.
Edited the question and added the OA
Intern
Intern
avatar
Joined: 15 Jul 2009
Posts: 5
Followers: 0

Kudos [?]: 5 [0], given: 0

Re: MGMAT question [#permalink]

Show Tags

New post 18 Apr 2010, 15:51
A - II only

P^2+P will always be even because p is odd adding an odd to an odd is even.

x can be 2 or 7 so it can be odd or even which makes it impossible for I or III to always be true
also, y can be odd or even

-ANy time an even number is in a multiple the product is even.
1 KUDOS received
Manager
Manager
avatar
Joined: 13 Dec 2009
Posts: 129
Followers: 6

Kudos [?]: 284 [1] , given: 10

Re: MGMAT question [#permalink]

Show Tags

New post 18 Apr 2010, 18:12
1
This post received
KUDOS
mads wrote:
If |x – (9/2) | = 5/2 , and if y is the median of a set of p consecutive integers, where p is odd, which of the following must be true?

I. \(xyp\)is odd

II. \(xy(p^2 + p)\) is even

III. \(x^2y^2p^2\) is even

A. II only
B. III only
C. I and III
D. II and III
E. I, II, and III


x is in range of 2 and 7 so it can be even or odd
y is median of set of odd integers so it can be even or odd
p is given as odd
using above information only II for sure can be inferred as even.
other two, either can be even or odd
correct response is A.
Intern
Intern
avatar
Joined: 04 May 2013
Posts: 47
Followers: 0

Kudos [?]: 7 [0], given: 7

Re: MGMAT question [#permalink]

Show Tags

New post 06 Jul 2013, 11:16
einstein10 wrote:
mads wrote:
If |x – (9/2) | = 5/2 , and if y is the median of a set of p consecutive integers, where p is odd, which of the following must be true?

I. \(xyp\)is odd

II. \(xy(p^2 + p)\) is even

III. \(x^2y^2p^2\) is even

A. II only
B. III only
C. I and III
D. II and III
E. I, II, and III


x is in range of 2 and 7 so it can be even or odd
y is median of set of odd integers so it can be even or odd
p is given as odd
using above information only II for sure can be inferred as even.
other two, either can be even or odd
correct response is A.



X is not between 2 and 7. X is either 2 or 7.
But the rest of the explanation is correct I believe.
GMAT Club Legend
GMAT Club Legend
User avatar
Joined: 09 Sep 2013
Posts: 13957
Followers: 590

Kudos [?]: 167 [0], given: 0

Premium Member
Re: If |x – 9/2| = 5/2, and if y is the median of a set of p [#permalink]

Show Tags

New post 21 Jul 2014, 22:25
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

GMAT Books | GMAT Club Tests | Best Prices on GMAT Courses | GMAT Mobile App | Math Resources | Verbal Resources

GMAT Club Legend
GMAT Club Legend
User avatar
Joined: 09 Sep 2013
Posts: 13957
Followers: 590

Kudos [?]: 167 [0], given: 0

Premium Member
Re: If |x – 9/2| = 5/2, and if y is the median of a set of p [#permalink]

Show Tags

New post 31 Mar 2016, 19:11
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

GMAT Books | GMAT Club Tests | Best Prices on GMAT Courses | GMAT Mobile App | Math Resources | Verbal Resources

Intern
Intern
avatar
Joined: 28 Apr 2016
Posts: 48
Followers: 0

Kudos [?]: 1 [0], given: 60

Re: If |x – 9/2| = 5/2, and if y is the median of a set of p [#permalink]

Show Tags

New post 14 May 2016, 22:46
given:
p is Odd
y is the median of odd numbers, hence y is Odd
x = solving the modulus you get 7 and 2. Hence x is Even or Odd

Therefore: p = O, y = O and x = O or E


Statement I = x*y*p = y*p*x = O x O x O/E = O x O/E = Odd or even. So False

Statement II = xy(p^2 + p) = O/E x O (O + O) = O/E x O(E) = O/E x E = Always Even. So true

Statement III. x^2y^2p^2 is even. E/O x O x O = Odd or even. Hence False.

Answer = A.





mads wrote:
If |x – 9/2| = 5/2, and if y is the median of a set of p consecutive integers, where p is odd, which of the following must be true?

I. xyp is odd
II. xy(p^2 + p) is even
III. x^2y^2p^2 is even

A. II only
B. III only
C. I and III
D. II and III
E. I, II, and III
SVP
SVP
User avatar
S
Joined: 17 Jul 2014
Posts: 2329
Location: United States (IL)
Concentration: Finance, Economics
Schools: Stanford '19 (S)
GMAT 1: 560 Q42 V26
GMAT 2: 550 Q39 V27
GMAT 3: 560 Q43 V24
GMAT 4: 650 Q49 V30
GPA: 3.92
WE: General Management (Transportation)
Followers: 23

Kudos [?]: 273 [0], given: 145

GMAT ToolKit User Premium Member Reviews Badge CAT Tests
Re: If |x – 9/2| = 5/2, and if y is the median of a set of p [#permalink]

Show Tags

New post 03 Oct 2016, 06:41
mads wrote:
If |x – 9/2| = 5/2, and if y is the median of a set of p consecutive integers, where p is odd, which of the following must be true?

I. xyp is odd
II. xy(p^2 + p) is even
III. x^2y^2p^2 is even

A. II only
B. III only
C. I and III
D. II and III
E. I, II, and III


I got to A.

from the given info, x is either 2 or 7.
p is definitely odd.
y can be either odd or even.

1. might be true. x can be 2, and in this case, xyp is even.
C and E are out.

2. xy(p^2 +p)
p is odd. p^2+p = even. so everything, regardless of x and y, will be even.
B is out.

3. x can be even or odd; y can be even or odd; p is odd.
since all 3 variables can be odd, there is a possibility that the number is not even.
D is out

A is the answer.
Manager
Manager
User avatar
B
Joined: 16 Mar 2016
Posts: 137
Location: France
GMAT 1: 660 Q47 V33
GPA: 3.25
Followers: 3

Kudos [?]: 28 [0], given: 0

GMAT ToolKit User
If |x – 9/2| = 5/2, and if y is the median of a set of p [#permalink]

Show Tags

New post 22 Oct 2016, 01:32
x= 7 or x=2, So x can be either odd or even

|x-9/2|=5/2, we have two different cases

1/ |x-9/2|>0 => |x-9/2|=x-9/2 and x>9/2
x-9/2 = 5/2 => x = 14/2 = 7

2/ |x-9/2|<0 => |x-9/2|=-(x-9/2) = -x + 9/2 and x<9/2
-x + 9/2 = 5/2 => x = 9/2 - 5/2 = 4/2 = 2

p is odd from the question

y can be either odd or even
{1,2,3} median is 2 even
{1,2,3,4,5} median is 3 odd



I. xyp is odd
Not necessarily if x is even

II. xy(p^2+p) is even
p is odd, so p² is odd and odd + odd = enve
so, xy(p2+p) is necessarily even


III. x^2y^2p^2 is even
not necessarily if x is odd, y is odd and p is odd

II only, answer choice A
If |x – 9/2| = 5/2, and if y is the median of a set of p   [#permalink] 22 Oct 2016, 01:32
    Similar topics Author Replies Last post
Similar
Topics:
1 Experts publish their posts in the topic For what value of x are the mode, the median and the average of set P Bunuel 4 08 Nov 2016, 22:52
3 Experts publish their posts in the topic If x is an integer, which of the following could be the median of Set Bunuel 4 27 Oct 2016, 23:49
11 Experts publish their posts in the topic The set P contains the points (x, y) on the coordinate plane that are Bunuel 5 22 Jul 2015, 01:04
4 Experts publish their posts in the topic If x is the median of the set {9/2, 11/3, 28/9, 21/5, x}, x emmak 6 15 Feb 2013, 11:01
1 Experts publish their posts in the topic If y((3x-5)/2) =y and y#0, then x = Walkabout 12 03 Dec 2012, 03:04
Display posts from previous: Sort by

If |x – 9/2| = 5/2, and if y is the median of a set of p

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  


GMAT Club MBA Forum Home| About| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group and phpBB SEO

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.