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If x and y are integers and 3^(x-4) = 3^(y+2), what is y in

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jsphcal
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If x and y are integers and 3^(x-4) = 3^(y+2), what is y in [#permalink] New post  Updated on: 08 Oct 2019, 08:21
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If x and y are integers and \(3^{(x-4)} = 3^{(y+2)}\), what is y in terms of x?

A. x - 6
B. x - 5
C. x - 2
D. x + 2
E. x + 6
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Originally posted by jsphcal on 06 Jun 2012, 19:16.
Last edited by Bunuel on 08 Oct 2019, 08:21, edited 2 times in total.
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jsphcal
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Re: If x and y are integers and 3^(x-4) = 3^(y+2), what is y in [#permalink] New post  06 Jun 2012, 19:27
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jsphcal wrote:
If x and y are integers and 3^x-^4 = 3^y+^2, what is y in terms of x?

A x - 6
B x - 5
C x - 2
D x + 2
E x + 6



since the bases are both 3 if i just isolate the exponents

x-4 = y+2 i can add 4 to get x = y+6

so x = y+6

since the question asks what is y in terms of x i can just subtract 6 from right side

so x-6 = y


I didnt take my time and when i attempted in powerprep, no i can see the answer is straight forward
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gmatsaga
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Re: If x and y are integers and 3^(x-4) = 3^(y+2), what is y in [#permalink] New post  06 Jun 2012, 19:26
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jsphcal wrote:
If x and y are integers and 3^x-^4 = 3^y+^2, what is y in terms of x?

A x - 6
B x - 5
C x - 2
D x + 2
E x + 6


Wait, how do you write down 3^y+^2 ?

Can you use parentheses so it'll be easier to understand.

Thanks
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JeffTargetTestPrep
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Re: If x and y are integers and 3^(x-4) = 3^(y+2), what is y in [#permalink] New post  01 Aug 2017, 17:12
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jsphcal wrote:
If x and y are integers and 3^(x-4) = 3^(y+2), what is y in terms of x?

A. x - 6
B. x - 5
C. x - 2
D. x + 2
E. x + 6


Since both bases are the same, we can drop the bases and equate the exponents:

x - 4 = y + 2

x - 6 = y

Answer: A
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Re: If x and y are integers and 3^(x-4) = 3^(y+2), what is y in [#permalink] New post  07 Jun 2012, 12:21
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Edited the question.

jsphcal wrote:
If x and y are integers and 3^(x-4) = 3^(y+2), what is y in terms of x?

A. x - 6
B. x - 5
C. x - 2
D. x + 2
E. x + 6


\(3^{x-4}=3^{y+2}\) --> \(x-4=y+2\) --> \(y=x-6\).

Answer: A.
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Re: If x and y are integers and 3^(x-4) = 3^(y+2), what is y in [#permalink] New post  17 Jun 2012, 12:55
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Answer: A

3^(x-4) = 3^(y+2)

Since the base is the same, I isolated the equations and solved for y.

x-4 = y+2
y=x-6
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Re: If x and y are integers and 3^(x-4) = 3^(y+2), what is y in [#permalink] New post  07 Jun 2012, 03:06
jsphcal wrote:
If x and y are integers and 3^x-^4 = 3^y+^2, what is y in terms of x?

A x - 6
B x - 5
C x - 2
D x + 2
E x + 6



The question seems confusing

is it 3^(x-4) = 3^(y+2)
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Re: If x and y are integers and 3^(x-4) = 3^(y+2), what is y in [#permalink] New post  30 Nov 2020, 08:13
jsphcal wrote:
If x and y are integers and \(3^{(x-4)} = 3^{(y+2)}\), what is y in terms of x?

A. x - 6
B. x - 5
C. x - 2
D. x + 2
E. x + 6

\(x - 4 = y + 2\)

So \(y = x - 6\), Answer must be (A)
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Re: If x and y are integers and 3^(x-4) = 3^(y+2), what is y in [#permalink] New post  07 Dec 2021, 16:00
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3^(x-4) = 3^(y+2)

Since the base is the same, we can equate the powers.

x-4 = y+ 2

y = x-6

Option A is the answer.

Thanks,
Clifin J Francis,
GMAT SME
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Re: If x and y are integers and 3^(x-4) = 3^(y+2), what is y in [#permalink] New post  09 Jan 2023, 02:44
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Re: If x and y are integers and 3^(x-4) = 3^(y+2), what is y in [#permalink]
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