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Re: If x and y are integers and x^2*y is a negative odd integer, which of [#permalink]
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x^2*y = negative odd integer

inference:
1. Odd * Odd = Odd
2. y is negative odd integer
3. x is odd (since its squared, the result is positive - so x could be either positive or negative).

Statement I - xy is odd, so is its sqaure - statement must be true
Statement II - xy may or may not be negative - statement may be true but NOT must
Statement III - x and y are odd, so Odd + Odd = Even - statement must be true

Answer is D - I and III only
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Re: If x and y are integers and x^2*y is a negative odd integer, which of [#permalink]
Option D

x & y are integers such that x^2*y = Negative Odd integer.
i.e., y = Negative Odd integer & x = Negative or Positive Odd integer

I. xy^2 is odd. = True
II. xy is negative. = +ve or -ve
III. x + y is even. = True
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Re: If x and y are integers and x^2*y is a negative odd integer, which of [#permalink]
Man I read this wrong x^2*y I read x^2y so I was really lost easier to read y*x^2

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Re: If x and y are integers and x^2*y is a negative odd integer, which of [#permalink]
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