GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 18 Nov 2019, 14:02

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# If x and y are integers and y^2(1+x)=1, what is the value of y?

Author Message
TAGS:

### Hide Tags

Manager
Joined: 29 May 2016
Posts: 96
Location: Czech Republic
Concentration: Finance, Strategy
GMAT 1: 700 Q47 V38
GPA: 3.94
WE: Corporate Finance (Investment Banking)
If x and y are integers and y^2(1+x)=1, what is the value of y?  [#permalink]

### Show Tags

Updated on: 13 Oct 2019, 08:35
1
00:00

Difficulty:

65% (hard)

Question Stats:

30% (01:07) correct 70% (01:11) wrong based on 37 sessions

### HideShow timer Statistics

If x and y are integers and $$y^2$$(1+x)=1, what is the value of y?

I) x=0

II) $$y^{999}≠1$$

Source: TargetTestPrep

Originally posted by Xin Cho on 13 Oct 2019, 08:21.
Last edited by Xin Cho on 13 Oct 2019, 08:35, edited 2 times in total.
Math Expert
Joined: 02 Sep 2009
Posts: 59125
Re: If x and y are integers and y^2(1+x)=1, what is the value of y?  [#permalink]

### Show Tags

13 Oct 2019, 08:26
Xin Cho wrote:
If x and y are integers and $$y^2$$(1+x)=1, what is the value of y?

I) x=0
II) $$y^{999}$$
Source: TargetTestPrep

Please edit the second statement. Thank you.
_________________
Math Expert
Joined: 02 Aug 2009
Posts: 8187
Re: If x and y are integers and y^2(1+x)=1, what is the value of y?  [#permalink]

### Show Tags

13 Oct 2019, 08:30
If x and y are integers and $$y^2$$(1+x)=1, what is the value of y?

I) x=0
$$y^2$$(1+x)=1......$$y^2*1=1...y^2=1$$, so y = 1 or -1
Insuff

II) $$y^{999}=1$$
y=1
Suff

B
_________________
SVP
Joined: 03 Jun 2019
Posts: 1849
Location: India
Re: If x and y are integers and y^2(1+x)=1, what is the value of y?  [#permalink]

### Show Tags

13 Oct 2019, 09:53
Xin Cho wrote:
If x and y are integers and $$y^2$$(1+x)=1, what is the value of y?

I) x=0

II) $$y^{999}≠1$$

Source: TargetTestPrep

Asked: If x and y are integers and $$y^2$$(1+x)=1, what is the value of y?

y^2 = 1/(1+x)
For y to be an integer, x=0 & y^2 = 1; y=1 or -1

I) x=0
y=1 or -1
NOT SUFFICIENT

II) $$y^{999}≠1$$
y ≠1
y = -1
SUFFICIENT

IMO B
_________________
"Success is not final; failure is not fatal: It is the courage to continue that counts."

Please provide kudos if you like my post. Kudos encourage active discussions.

My GMAT Resources: -

Efficient Learning
All you need to know about GMAT quant

Tele: +91-11-40396815
Mobile : +91-9910661622
E-mail : kinshook.chaturvedi@gmail.com
Intern
Joined: 22 Sep 2018
Posts: 38
Re: If x and y are integers and y^2(1+x)=1, what is the value of y?  [#permalink]

### Show Tags

13 Oct 2019, 12:25
Kinshook wrote:
Xin Cho wrote:
If x and y are integers and $$y^2$$(1+x)=1, what is the value of y?

I) x=0

II) $$y^{999}≠1$$

Source: TargetTestPrep

Asked: If x and y are integers and $$y^2$$(1+x)=1, what is the value of y?

y^2 = 1/(1+x)
For y to be an integer, x=0 & y^2 = 1; y=1 or -1

I) x=0
y=1 or -1
NOT SUFFICIENT

II) $$y^{999}≠1$$
y ≠1
y = -1
SUFFICIENT

IMO B

Hi, I don't understand the reasoning behind the second statement could you please explain why did you consider y= -1 ?
Manager
Joined: 29 May 2016
Posts: 96
Location: Czech Republic
Concentration: Finance, Strategy
GMAT 1: 700 Q47 V38
GPA: 3.94
WE: Corporate Finance (Investment Banking)
Re: If x and y are integers and y^2(1+x)=1, what is the value of y?  [#permalink]

### Show Tags

13 Oct 2019, 13:14
Fatineel

From the prompt we know that $$y^2$$(1+x)=1. If x is negative then the whole left side is negative $$y^2$$(1+x), which will not equal to 1.
If x is positive then we get $$y^2$$(positive) which will be inevitably greater than 1. Notice that the prompt states that both x and y are integers.
What does this mean? x has to equal to zero.

If x=0 we can simplify to $$y^2$$(1+0)=1 ==> $$y^2$$=1
Now, y can be either 1 or -1. As $$1^2$$=1 or $$(-1)^2$$=1.

Makes sense?
Intern
Joined: 09 Jun 2019
Posts: 11
Re: If x and y are integers and y^2(1+x)=1, what is the value of y?  [#permalink]

### Show Tags

13 Oct 2019, 13:55
From the prompt we know that $$y^2$$(1+x)=1. If x is negative then the whole left side is negative $$y^2$$(1+x), which will not equal to 1.
If x is positive then we get $$y^2$$(positive) which will be inevitably greater than 1. Notice that the prompt states that both x and y are integers.
What does this mean? x has to equal to zero.

If x=0 we can simplify to $$y^2$$(1+0)=1 ==> $$y^2$$=1
Now, y can be either 1 or -1. As $$1^2$$=1 or $$(-1)^2$$=1.

Makes sense?[/quote]

Great stuff!
Re: If x and y are integers and y^2(1+x)=1, what is the value of y?   [#permalink] 13 Oct 2019, 13:55
Display posts from previous: Sort by