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If x and y are positive integers, what percent of three more than y is

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SVP
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If x and y are positive integers, what percent of three more than y is  [#permalink]

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New post 24 Sep 2017, 12:22
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64% (00:54) correct 36% (01:18) wrong based on 118 sessions

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If x and y are positive integers, what percent of three more than y is twice the value of x?

A 1/200x(y + 3)
B y + 3/200x
C 100(y + 3)/2x
D (200x/y) + 3
E 200x/(y + 3)

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If x and y are positive integers, what percent of three more than y is  [#permalink]

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New post 24 Sep 2017, 13:20
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SajjadAhmad wrote:
If x and y are positive integers, what percent of three more than y is twice the value of x?

A 1/200x(y + 3)
B y + 3/200x
C 100(y + 3)/2x
D (200x/y) + 3
E 200x/(y + 3)

Rewrite: twice the value of x is what percent of three more than y?

Twice the value of x \(= 2x\)
Three more than y = \(y + 3\)

\(\frac{part}{whole} * 100 =\) percent

\(\frac{2x}{(y + 3)} * 100 =\) percent

percent = \(\frac{200x}{(y + 3)}\)

Answer E
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Re: If x and y are positive integers, what percent of three more than y is  [#permalink]

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New post 24 Sep 2017, 14:28
SajjadAhmad wrote:
If x and y are positive integers, what percent of three more than y is twice the value of x?

A 1/200x(y + 3)
B y + 3/200x
C 100(y + 3)/2x
D (200x/y) + 3
E 200x/(y + 3)


The answer should be E as follows.

Let the percentage we have to find out is z.

As per the condition given,

\((\frac{z}{100})*(y+3)=2x\) ==> \(z=\frac{2x*100}{(y+3)}\) ==>\(\frac{200x}{(y+3)}\)

Hence answer is E
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Re: If x and y are positive integers, what percent of three more than y is  [#permalink]

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New post 26 Sep 2017, 16:34
SajjadAhmad wrote:
If x and y are positive integers, what percent of three more than y is twice the value of x?

A 1/200x(y + 3)
B y + 3/200x
C 100(y + 3)/2x
D (200x/y) + 3
E 200x/(y + 3)


We can translate “what percent of three more than y is twice the value of x” into an expression in which n is the percent:

(n/100)(y + 3) = 2x

n/100 = (2x)/(y + 3)

n = (200x)/(y + 3)

Answer: E
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Re: If x and y are positive integers, what percent of three more than y is &nbs [#permalink] 26 Sep 2017, 16:34
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