If x and y are real numbers and a^2x*a^2y = 81, what is the value of x

Regarding statment 2 , in your second option X need to be in that case 1/2 , and the question did state "Real number " can you please explain that one ?

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.
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The first step of the VA (Variable Approach) method is to modify the original condition and the question. We then recheck the question. We should simplify conditions if necessary.

\(a^{2x} \cdot a^{2y} = 81\)
\(⇔ a^{2x+2y} = 3^4\)
\(⇔ a^{2(x+y)} = 3^4\)

Then, if \(a = 3\), then we have \(2(x+y) = 4\) or \(x+y = 2\).
Thus condition 1) alone is sufficient.

Condition 2)
If \(x = 1, y = 1\), then we have \(a^4 = 81\), which implies \(a = 3\) or \(-3\).

Since condition 2) does not yield a unique solution, it is not sufficient.

Therefore, A is the answer.

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