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If x and y are selected from 2, 3, 4, 5 and 6. What is the

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Senior Manager
Joined: 08 Aug 2005
Posts: 251

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If x and y are selected from 2, 3, 4, 5 and 6. What is the [#permalink]

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26 Apr 2006, 03:44
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If x and y are selected from 2, 3, 4, 5 and 6. What is the probability that x*y is divisible by 4?

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GMAT Club Legend
Joined: 07 Jul 2004
Posts: 5034

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Location: Singapore

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26 Apr 2006, 04:20
It's divisible by 4 if the product is a multiple of 4

Possiblilites = 2*4, 2*6, 3*4, 4*6 --> 4 ways

Number of ways to pick any 2 numbers = 5C2 = 10 ways

P = 4/10 = 2/5

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Manager
Joined: 23 Jan 2006
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26 Apr 2006, 07:34

same way to solve, just add one case.

so 5/10 or 1/2

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Manager
Joined: 20 Nov 2004
Posts: 108

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26 Apr 2006, 13:29
First of all, the answer depends on whether x and y can be the same
number. I don't think that the question is clear in regard to that.

If x and y can be the same:

{2,2}
{2,4}
{2,6}
{3,4}
{4,2}
{4,3}
{4,4}
{4,5}
{4,6}
{5,4}
{6,2}
{6,4}
{6,6}

So 13/25.

==

If x and y can't be the same:

{2,4}
{2,6}
{3,4}
{4,2}
{4,3}
{4,5}
{4,6}
{5,4}
{6,2}
{6,4}

So 10/20 = 1/2.

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Senior Manager
Joined: 08 Jun 2004
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27 Apr 2006, 08:38
1/2

Total 5C2 = 10

Favourable possibilities = 2*4; 2*6; 3*4; 4*5; 4*6.
5/10=1/2.

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Intern
Joined: 02 Mar 2006
Posts: 21

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28 Apr 2006, 06:25
total no.of ways for selecting xand y = 5C2 = 10

divisible by 4... donein two ways

1. multiplication of two een numbers = 3C2 = 3
2. multiplication of an odd number by 4 = 1.2C1 = 2

therefore 5/10 = 1/2

Kudos [?]: 2 [0], given: 0

28 Apr 2006, 06:25
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