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# If x and y are +ve, is y > 2? 1. x > 2y 22. x < y+2

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If x and y are +ve, is y > 2? 1. x > 2y 22. x < y+2 [#permalink]

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18 Aug 2004, 16:11
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If x and y are +ve, is y > 2?
1. x > 2y
22. x < y+2
Senior Manager
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18 Aug 2004, 16:21
I would say C.

Combining
x > 2y
And
x < y+2

we get 2Y < Y + 2
subtracting Y we get
Y < 2
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18 Aug 2004, 19:53
from 1, x/2 > y. sufficient. we know x is positive, so x can take values 1,2,3,4,... etc
so y will always be less than values 1/2,1/3,1/4,1/5.. etc depending on what value x takes on.
so from 1, we know y >2 will never happen

from 2, x-2 < y, for 2 < y, x have to be 4 and above. but we only know x and y are positive, and x could be 1. so 2 is insufficient.

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18 Aug 2004, 20:26
C for me too. I key'ed in the numbers, only for y<2 both statements hold good.

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18 Aug 2004, 20:30
Hello wilfred

You have mentioned ....

Quote:
from 1, x/2 > y. sufficient. we know x is positive, so x can take values 1,2,3,4,... etc
so y will always be less than values 1/2,1/3,1/4,1/5.. etc depending on what value x takes on.
so from 1, we know y >2 will never happen

This is not correct.

X>2y ---> if x is 1 then y is 1/2, if x is 10, then y=5, Hence this does not stand good.

C is the answer. Combing both we know that, Y is less than 2.
_________________

Giving another SHOT

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18 Aug 2004, 20:31
ah !! i'm always prone to these errors... thanks for pointing them out carsen !
18 Aug 2004, 20:31
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