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Each week we'll be posting several questions from The Official Guide for GMAT® Review, 13th Edition and then after couple of days we'll provide Official Answer (OA) to them along with a slution.

We'll be glad if you participate in development of this project: 1. Please provide your solutions to the questions; 2. Please vote for the best solutions by pressing Kudos button; 3. Please vote for the questions themselves by pressing Kudos button; 4. Please share your views on difficulty level of the questions, so that we have most precise evaluation.

Is \(\frac{x}{y}>1\)? --> as given that \(y\) is positive we can safely multiply both parts of the inequality by it --> so the question becomes "is \(x>y\)?" OR: is \(x-y>0\)?

(1) xy > 1 --> product of two numbers is more than one we can't say which one is greater. Not sufficient.

(2) x - y > 0. Directly answers the questions. Sufficient.

Re: If x and yare positive, is x/y greater than 1 ? [#permalink]

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24 Sep 2012, 08:17

2

This post received KUDOS

If x and yare positive, is x/y greater than 1 ?

(1) xy > 1 (2) x - y >O

(1) INFUFF: If x*y is greater than 1, it means that either X or Y is greater than two, the problem is that we do not know which one. X/Y could be 2/1 or 1/2 (2) SUFF (assuming integers) if z-y>0, x>y so necessarily x/y greater than one

IMO B
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Re: If x and yare positive, is x/y greater than 1 ? [#permalink]

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24 Sep 2012, 09:12

Bunuel wrote:

If x and y are positive, is x/y greater than 1 ?

(1) xy > 1 (2) x - y >O

x > 0; y > 0 x/y > 1? or x > 1? (safe multiply as both x and y are +ve)

(1) xy > 1 There can be many values of x and y which can satisfy this equation. eg. x= 2 and y = 0.75 is OK x = .75 and y = 2 is also OK Not sufficient

Is \(\frac{x}{y}>1\)? --> as given that \(y\) is positive we can safely multiply both parts of the inequality by it --> so the question becomes "is \(x>y\)?" OR: is \(x-y>0\)?

(1) xy > 1 --> product of two numbers is more than one we can't say which one is greater. Not sufficient.

(2) x - y > 0. Directly answers the questions. Sufficient.

Answer: B.

Kudos points given to everyone with correct solution. Let me know if I missed someone.
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Re: If x and yare positive, is x/y greater than 1 ? [#permalink]

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06 May 2016, 01:27

good thing about this question is we are given that x and y are positive. is x/y >1 ? since y is positive , we can multiply the inequality both side with y . now the question changes to y * x/y > y => is x >y ?

from stat 1 xy > 1 , well in this case x = 2 , y = 2 or x= 2 and y = 1 (both satisfies stat. 1 ) which does not give us x>y insufficient

from stat 2 x-y >0 ofcourse x > y that is why x-y is greater than 0. correct option - B.

Since x and y are positive we can multiply both sides of our inequality by y to obtain:

Is x > y?

Statement One Alone:

xy > 1

Knowing that the product of xy is greater than 1 does not allow us to determine whether x is greater than y. For example, if x = 2 and y = 1, then x > y, but if x = 1 and y = 2, then x < y. Statement one alone is not sufficient to answer the question. We can eliminate answer choices A and D.

Statement Two Alone:

x – y > 0

We can add y to both sides of the inequality to obtain:

x > y

Statement two is sufficient to answer the question.

The answer is B.
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