If x and yare positive, is x/y greater than 1 ? : GMAT Data Sufficiency (DS)
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# If x and yare positive, is x/y greater than 1 ?

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If x and yare positive, is x/y greater than 1 ? [#permalink]

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24 Sep 2012, 04:23
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The Official Guide for GMAT® Review, 13th Edition - Quantitative Questions Project

If x and yare positive, is x/y greater than 1 ?

(1) xy > 1
(2) x - y > 0

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Question: 50
Page: 279
Difficulty: 600

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Re: If x and yare positive, is x/y greater than 1 ? [#permalink]

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24 Sep 2012, 04:24
SOLUTION

If x and yare positive, is x/y greater than 1 ?

Is $$\frac{x}{y}>1$$? --> as given that $$y$$ is positive we can safely multiply both parts of the inequality by it --> so the question becomes "is $$x>y$$?" OR: is $$x-y>0$$?

(1) xy > 1 --> product of two numbers is more than one we can't say which one is greater. Not sufficient.

(2) x - y > 0. Directly answers the questions. Sufficient.

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Re: If x and yare positive, is x/y greater than 1 ? [#permalink]

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24 Sep 2012, 04:41
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Re: If x and yare positive, is x/y greater than 1 ? [#permalink]

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24 Sep 2012, 07:17
2
KUDOS
If x and yare positive, is x/y greater than 1 ?

(1) xy > 1
(2) x - y >O

(1) INFUFF: If x*y is greater than 1, it means that either X or Y is greater than two, the problem is that we do not know which one. X/Y could be 2/1 or 1/2
(2) SUFF (assuming integers) if z-y>0, x>y so necessarily x/y greater than one

IMO B
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Re: If x and yare positive, is x/y greater than 1 ? [#permalink]

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24 Sep 2012, 08:12
Bunuel wrote:

If x and y are positive, is x/y greater than 1 ?

(1) xy > 1
(2) x - y >O

x > 0; y > 0
x/y > 1?
or x > 1? (safe multiply as both x and y are +ve)

(1)
xy > 1
There can be many values of x and y which can satisfy this equation.
eg. x= 2 and y = 0.75 is OK
x = .75 and y = 2 is also OK
Not sufficient

(2)
x - y > 0
=> x > y
Sufficient

hence B
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Re: If x and yare positive, is x/y greater than 1 ? [#permalink]

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28 Sep 2012, 04:52
SOLUTION

If x and yare positive, is x/y greater than 1 ?

Is $$\frac{x}{y}>1$$? --> as given that $$y$$ is positive we can safely multiply both parts of the inequality by it --> so the question becomes "is $$x>y$$?" OR: is $$x-y>0$$?

(1) xy > 1 --> product of two numbers is more than one we can't say which one is greater. Not sufficient.

(2) x - y > 0. Directly answers the questions. Sufficient.

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Re: If x and yare positive, is x/y greater than 1 ? [#permalink]

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06 May 2016, 00:27
is x/y >1 ?
since y is positive ,
we can multiply the inequality both side with y .
now the question changes to
y * x/y > y
=> is x >y ?

from stat 1
xy > 1 , well in this case
x = 2 , y = 2 or x= 2 and y = 1 (both satisfies stat. 1 )
which does not give us x>y
insufficient

from stat 2
x-y >0
ofcourse x > y that is why x-y is greater than 0.
correct option - B.
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Re: If x and yare positive, is x/y greater than 1 ? [#permalink]

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14 May 2016, 06:35
Bunuel wrote:
The Official Guide for GMAT® Review, 13th Edition - Quantitative Questions Project

If x and yare positive, is x/y greater than 1 ?

(1) xy > 1
(2) x - y > 0

Solution:

We are asked is x/y > 1?

Since x and y are positive we can multiply both sides of our inequality by y to obtain:

Is x > y?

Statement One Alone:

xy > 1

Knowing that the product of xy is greater than 1 does not allow us to determine whether x is greater than y. For example, if x = 2 and y = 1, then x > y, but if x = 1 and y = 2, then x < y. Statement one alone is not sufficient to answer the question. We can eliminate answer choices A and D.

Statement Two Alone:

x – y > 0

We can add y to both sides of the inequality to obtain:

x > y

Statement two is sufficient to answer the question.

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Re: If x and yare positive, is x/y greater than 1 ? [#permalink]

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30 Jun 2016, 04:06
(1) is not sufficient, because it is possible that x=1, y=2. So, while xy>1, but x/y <1.

On the other hand, it is possible that x=2, y=1. So, while xy>1, but x/y >1.

(2) is sufficient because it tells that x>y. Since the question mentions that x and y are positive, then it has to be the case that x/y>1.

Re: If x and yare positive, is x/y greater than 1 ?   [#permalink] 30 Jun 2016, 04:06
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