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# If x does NOT equal -y, does (x-y)/(x+y) > 1? (1) x >

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If x does NOT equal -y, does (x-y)/(x+y) > 1? (1) x > [#permalink]

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21 Apr 2007, 08:46
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If x does NOT equal -y, does (x-y)/(x+y) > 1?

(1) x > 0
(2) y < 0

Highlight! -> Can I multiply both sides by (x+y) and have it x-y > x+y?

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Manager
Joined: 18 Apr 2007
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21 Apr 2007, 09:05
DS is not my strong suit, but I'm going to take a stab at this:

The only way (x-y)/(x+y) can be greater than 1 is if (x-y) is greater than (x+y). The only way this can happen is if y is negative and x is positive. Therefore,

A) x>0 - this tells us nothing about y - Not Sufficient
B) y<0 - this tells us nothing about x - Not Sufficient

Is my reasoning logical?

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Intern
Joined: 28 Dec 2006
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21 Apr 2007, 10:28
Quote:
The only way this can happen is if y is negative and x is positive.

This is not true.

Ex 1: x = 1, y = -3/4
(1 + 3/4)/(1 - 3/4) = (7/4)/(1/4) = 7

Ex 2: x=1, y=-3
(1 + 3)/(1-3) = 4/-2 = -2

I believe the answer is E.

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Current Student
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21 Apr 2007, 10:30
I am going with E on this..unless we know how big Y is compared to X we are not sure of the sign of the equation..

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Intern
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21 Apr 2007, 10:48
Quote:
Highlight! -> Can I multiply both sides by (x+y) and have it x-y > x+y?

You cannot because (x+y) could be a negative number.

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Manager
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21 Apr 2007, 21:28
You are right...I stand corrected. Thanks for the insight.

B

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21 Apr 2007, 21:28
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