emailmkarthik wrote:

Hey Bunuel,

Do you have any alternate easier method to tackle this problem?

If x is a number such that –2 ≤ x ≤ 2, which of the following has the largest possible absolute value?A. 3x – 1

B. x^2 + 1

C. 3 – x

D. x – 3

E. x^2 – x

First of all notice that we can eliminate options C and D right away: \(|3-x|=|x-3|\), so these two options will have the same maximum value and since we cannot have two correct answers in PS questions then none of them is correct.

Evaluate each option by plugging min and max possible values of x:

A. 3x – 1 --> max for x=-2 --> |3*(-2)-1|=7.

Attachment:

MSP40111b1fh8bi1bf48ff500001bihb6c5hie997cf.gif

B. x^2 + 1 --> max for x=-2 or x=2 --> |2^2 + 1|=5.

Attachment:

MSP566209hcf53gca1831500002g3b78339ag7a6gh.gif

E. x^2 – x --> max for x=-2 --> |(-2)^2 - (-2)|=6.

Attachment:

MSP5861i671ha12e2ie48c00005gbb4caa2heiag53.gif

Answer: A.

Not necessary for solving this question but how did you draw graph of x2 -x ?