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Re: Inequality - Absolute value [#permalink]
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gmat1220 wrote:
hello shrouded1
I don't understand your last statement. Pls can you elaborate.

(Its easy to tell what the global min for these simple quadratic functions is knowing where there roots are, it is half way between the roots)

On way to get the global min is applying the calculus. -
y = x^2+1
dy/dx = 0 or 2x = 0. So the min occurs at x=0

Similarly y = x^2-x
dy/dx = 0 or 2x - 1 = 0 . So the min occurs at x = 1/2 = 0.5


Thats implicitly what I did. But I used a little trick so I dont have to do the calculations.
For any quadratic function with real roots, the minima/maxima (depending on wether the coefficient of x^2 is positive or negative) will occur at the mean of the roots. (This is very easy to prove, all I am saying is that the minima is -b/2a, which you can show by differentiation).

So for x^2-x = x(x-1) the roots are 0,1 and the minima will be at 0.5

For x^2+1, the roots are not real, but this function is simply a vertically translated version of x^2=0, hence it also minimizes/maximizes at the same level which is x=0.



Generalizing, you can always use the fornula x=(-b/2a) for the min or max valuation
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If x is a number such that –2 ≤ x ≤ 2 which of the following [#permalink]
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If x is a number such that –2 ≤ x ≤ 2, which of the following has the largest possible absolute value?

A. 3x – 1
B. x^2 + 1
C. 3 – x
D. x – 3
E. x^2 – x

First of all notice that we can eliminate options C and D right away: \(|3-x|=|x-3|\), so these two options will have the same maximum value and since we cannot have two correct answers in PS questions then none of them is correct.

Evaluate each option by plugging min and max possible values of x:

A. 3x – 1 --> max for x=-2 --> |3*(-2)-1|=7.


B. x^2 + 1 --> max for x=-2 or x=2 --> |2^2 + 1|=5.


E. x^2 – x --> max for x=-2 --> |(-2)^2 - (-2)|=6.


Answer: A.

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Re: If x is a number such that –2 ≤ x ≤ 2 which of the following [#permalink]
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x is a number such that –2 ≤ x ≤ 2

In order to solve this problem you can substitute values of +2 and -2 based and can quickly get the absolute value.

A. 3x – 1 =====> 3*-2-1 = -7 = l-7l = 7 ======> Maximum ab. value
B. x^2 + 1 =====> 4+1 = 5
C. 3 – x =====> 2-(-2) = 4
D. x – 3 =====> 3-(-2) = 5
E. x^2 – x =====> 4-(-2) = 6

So, only 7 is the maximum value.

A is the correct answer.
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Re: If x is a number such that 2 x 2 which of the following [#permalink]
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Re: If x is a number such that 2 x 2 which of the following [#permalink]
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