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# If x is a positive integer, is the remainder 0 when

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Manager
Joined: 11 Jan 2007
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Location: Bangkok
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If x is a positive integer, is the remainder 0 when [#permalink]

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09 Jul 2007, 20:27
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Q32:
If x is a positive integer, is the remainder 0 when (3^x + 1)/10?
(1) x = 3n + 2, where n is a positive integer.
(2) x > 4
_________________

cool

Director
Joined: 14 Jan 2007
Posts: 775
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Kudos [?]: 148 [0], given: 0

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10 Jul 2007, 02:31
Should be 'E'

Stmt1:
x= 5, remiander is 4
x=14 , remainder is 0
So INSUFF

Stmt2:
same as above. So inSUFF

Taken them together:
INSUFF
Manager
Joined: 07 Feb 2007
Posts: 212
Followers: 2

Kudos [?]: 14 [0], given: 0

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10 Jul 2007, 05:12
Himalayan wrote:
jet1445 wrote:
Q32: If x is a positive integer, is the remainder 0 when (3^x + 1)/10?
(1) x = 3n + 2, where n is a positive integer.
(2) x > 4

A.

A only if the first condition is: x=4n+2.
Director
Joined: 26 Feb 2006
Posts: 901
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11 Jul 2007, 21:56
Himalayan wrote:
jet1445 wrote:
Q32: If x is a positive integer, is the remainder 0 when (3^x + 1)/10?
(1) x = 3n + 2, where n is a positive integer.
(2) x > 4

A.

whenever i take too quick decision, i fall on the trap. therefore i slipped on this one. i thought x = 3n + 2 has a pattern but when x = 4n + 2, then only it would have a pattern.

agree with you guys.
thanks for good job.
Director
Joined: 09 Aug 2006
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12 Jul 2007, 03:08
[quote="vshaunak@gmail.com"]Should be 'E'

Stmt1:
x= 5, remiander is 4
x=14 , remainder is 0
So INSUFF

Stmt2:
same as above. So inSUFF

Taken them together:
INSUFF[/quote

Did you work your way up to calculating (the units digit of) x=14? If not, how did you figure out that x=14 will yield a 0? Thanks.
12 Jul 2007, 03:08
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