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# If x is a positive integer such that

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Re: If x is a positive integer such that [#permalink]
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x^2+5x-14=0
x^2+7x-2x-14=0
x(x+7)-2(x+7)=0
(x-2)(x+7)=0

Hence
either x-2=0 => x=2
or x+7=0 => x=-7

But it is mentioned in the question statement that x is positive.

So x=2.

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Re: If x is a positive integer such that [#permalink]
Just to post a different approach, the question is for positive value of 2...so Only D or E will be the answer. Substitute these in the equation to see which satisfies.

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Re: If x is a positive integer such that [#permalink]
If x is a positive integer such that $$x^2 + 5x − 14 = 0$$, what is the value of x ?

A. −7
B. −5
C. 0
D. 2
E. 5

$$x^2 + 5x − 14 = 0$$

Or, $$x^2 + 7x − 2x − 14 = 0$$

Or, $$x ( x + 7 ) − 2 ( x + 7 ) = 0$$

Or, $$( x + 7 ) ( x − 2 ) = 0$$

So, $$x = 2$$ or $$x = −7$$

Answer will be (D) $$x = 2$$
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Re: If x is a positive integer such that [#permalink]
1
Kudos
If x is a positive integer such that x^2 + 5x − 14 = 0, what is the value of x ?

A. −7
B. −5
C. 0
D. 2
E. 5

x^2 + 5x − 14 = 0

(x + 7)(x - 2) = 0

x = -7 or x = 2

Since x must be positive, 2 is the correct answer.