AnupamKT wrote:

sahilkak wrote:

If x is a positive integer, which of the following is not necessarily a divisor of x(x+1)(x+2)x(x+1)(x+2)?

a)x

b)2

c)3

d)4

e)6

IMO, Answer should be "C". Please explain how OA is "D".

My solution:

If x= Odd:

Then => x(x+1)(x+2)x(x+1)(x+2)= Even

If x=Even:

Then => x(x+1)(x+2)x(x+1)(x+2)= Even

In both the cases, expression yields Even no. hence This expression can be divisible by all mentioned in the above options except "C" i.e. 3.

Please correct me if i am wrong.

i was also mistaken in this question:

Here is official explanation

We’ll go for ALTERNATIVE since we’re asked about an expression with variables.

When looking at the answers, xx is definitely a divisor, since it is a multiplier in the expression itself. But what about the rest of the answers? Since this is an expression with only letters, we can pick a number: x=1x=1 gives us 1×2×3=61×2×3=6. So 2, 3, and 6 are all divisors of 6, but 4 isn’t.

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