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If X is a repeating decimal = 0.TBCDBCD, where T, B, C, and

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Manager
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Joined: 14 May 2009
Posts: 191

Kudos [?]: 48 [0], given: 1

Schools: Stanford, Harvard, Berkeley, INSEAD
Re: Challenge: Can you crack THIS? [#permalink]

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New post 07 Jun 2009, 01:26
And also, what if there is another value s.t. X=9115/N is equal to .TBCDBCD..... such that T != 9?

You haven't shown that either, you're assuming there is only one answer.

[deleted an attitude comment]
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Hades

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Re: Challenge: Can you crack THIS? [#permalink]

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New post 07 Jun 2009, 01:37
Hades wrote:
And also, what if there is another value s.t. X=9115/N is equal to .TBCDBCD..... such that T != 9?

You haven't shown that either, you're assuming there is only one answer.

[deleted an attitude comment]



Watch your language and attitude
Nobody is obliged to show you anything. I am closing this thread for now. If anyone has questions about it, please PM me and I will reopen.
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Kudos [?]: 28475 [0], given: 5105

Re: Challenge: Can you crack THIS?   [#permalink] 07 Jun 2009, 01:37

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If X is a repeating decimal = 0.TBCDBCD, where T, B, C, and

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